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lozanna [386]
3 years ago
13

Which of the following suggestions would best help alleviate the Gulf of Mexico dead zone?

Engineering
1 answer:
JulijaS [17]3 years ago
3 0

The answer has to be cut down on gas emissions. This can cut down emissions to the dead zone.

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Birdie Par owns a company that makes golf gloves. She is thinking about introducing a new glove, which would require an addition
melamori03 [73]

Birdie's company will make a profit of $30,000 if she sells 3,000 gloves at the $15 price.

Step-by-step Solution:

Break even point= fixed cost/ selling price - variable cost

here the fixed cost is= $20,000

selling price= $15 and variable cost = $5

BEP= 20,000/ 15-5= 20,000/10= 2000 units

b. if they sell 3000 gloves, the contribution profit will be

total revenue= 3000*$15= $45,000

contribution= selling price- variable cost, 15-5= $10 per unit

the profit is= 3000*$10= $30,000

What is  variable cost?

A variable cost is one that varies in relation to either the volume of production or the number of services provided. There should be no variable costs if no production or services are provided. Variable costs should rise in tandem with increases in production or services.

To learn more about Profit Calculation, visit: brainly.com/question/28177180

#SPJ1

3 0
1 year ago
Scanning the road can be thought of as
maw [93]

Answer:

Observational Skills

Explanation:

Observing the area also known as scanning the scene

5 0
3 years ago
Read 2 more answers
Air enters the combustor of a jet engine at p1=10 atm, T1=1000°R, and M1=0.2. Fuel is injected and burned, with a fuel/air mass
snow_lady [41]

Answer:

M2 = 0.06404

P2 = 2.273

T2 = 5806.45°R

Explanation:

Given that p1 = 10atm, T1 = 1000R, M1 = 0.2.

Therefore from Steam Table, Po1 = (1.028)*(10) = 10.28 atm,

To1 = (1.008)*(1000) = 1008 ºR

R = 1716 ft-lb/slug-ºR cp= 6006 ft-lb/slug-ºR fuel-air ratio (by mass)

F/A =???? = FA slugf/slugaq = 4.5 x 108ft-lb/slugfx FA slugf/sluga = (4.5 x 108)FA ft-lb/sluga

For the air q = cp(To2– To1)

(Exit flow – inlet flow) – choked flow is assumed For M1= 0.2

Table A.3 of steam table gives P/P* = 2.273,

T/T* = 0.2066,

To/To* = 0.1736 To* = To2= To/0.1736 = 1008/0.1736 = 5806.45 ºR Gives q = cp(To* - To) = (6006 ft-lb/sluga-ºR)*(5806.45 – 1008)ºR = 28819500 ft-lb/slugaSetting equal to equation 1 above gives 28819500 ft-lb/sluga= FA*(4.5 x 108) ft-lb/slugaFA =

F/A = 0.06404 slugf/slugaor less to prevent choked flow at the exit

5 0
3 years ago
Question 9.1 from the textbook. Consider the following workload: Process Burst Time Priority Arrival Time P1 50 4 0 P2 20 1 20 P
Marizza181 [45]

Answer:

Explanation:

The schedule using shortest remaining time, non-preemptive priority and round Robin with quantum number 30 is shown in the attached file, please kindly go through it to access the answer.

5 0
3 years ago
A 1000-turn coil of wire 1.0 cm in diameter is in a magnetic field that increases from 0.10 T to 0.30 T in 10 ms. The axis of th
ddd [48]

emf generated by the coil is 1.57 V

Explanation:

Given details-

Number of turns of wire- 1000 turns

The diameter of the wire coil- 1 cm

Magnetic field (Initial)= 0.10 T

Magnetic Field (Final)=0.30 T

Time=10 ms

The orientation of the axis of the coil= parallel to the field.

We know that EMF of the coil is mathematically represented as –

E=N(ΔФ/Δt)

Where E= emf generated

ΔФ= change inmagnetic flux

Δt= change in time

N= no of turns*area of the coil

Substituting the values of the above variables

=1000*3.14*0.5*10-4

=.0785

E=0.0785(.2/10*10-3)

=1.57 V

Thus, the emf generated is 1.57 V

4 0
3 years ago
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