This is the answer to Question 5
<span>Due that we already know the horizontal cross-sectional area of the ship, which is 2800 m2 and we are going to understand that value keeps constant for the whole 9.5 of height of the ship from the waterline till the new waterline after unloading, then we just need to calculate the volume as follows:
V = A * H , where V is volume, A is area and H is height
V= 2,800 * 9.5 = 26,600 m3
So this volum of 26,600 cubic meters is the volum of freshwater delivered in the island.</span>
Answer:
An atom with a closed shell of valence electrons (corresponding to an electron configuration s2p6) tends to be chemically inert. An atom with one or two valence electrons more than a closed shell is highly reactive, because the extra valence electrons are easily removed to form a positive ion.Explanation:
Answer:![3.874 m/s^2](https://tex.z-dn.net/?f=3.874%20m%2Fs%5E2)
Explanation:
Given
Car speed decreases at a constant rate from 64 mi/h to 30 mi/h
in 3 sec
![60mi/h \approx 26.8224m/s](https://tex.z-dn.net/?f=60mi%2Fh%20%5Capprox%2026.8224m%2Fs)
![34mi/h \approx 15.1994 m/s](https://tex.z-dn.net/?f=34mi%2Fh%20%5Capprox%2015.1994%20m%2Fs)
we know acceleration is given by ![=\frac{velocity}{Time}](https://tex.z-dn.net/?f=%3D%5Cfrac%7Bvelocity%7D%7BTime%7D)
![a=\frac{15.1994-26.8224}{3}](https://tex.z-dn.net/?f=a%3D%5Cfrac%7B15.1994-26.8224%7D%7B3%7D)
![a=-3.874 m/s^2](https://tex.z-dn.net/?f=a%3D-3.874%20m%2Fs%5E2)
negative indicates that it is stopping the car
Distance traveled
![v^2-u^2=2as](https://tex.z-dn.net/?f=v%5E2-u%5E2%3D2as)
![\left ( 15.1994\right )^2-\left ( 26.8224\right )^2=2\left ( -3.874\right )s](https://tex.z-dn.net/?f=%5Cleft%20%28%2015.1994%5Cright%20%29%5E2-%5Cleft%20%28%2026.8224%5Cright%20%29%5E2%3D2%5Cleft%20%28%20-3.874%5Cright%20%29s)
![s=\frac{488.419}{2\times 3.874}](https://tex.z-dn.net/?f=s%3D%5Cfrac%7B488.419%7D%7B2%5Ctimes%203.874%7D)
s=63.038 m
Answer:3,45 x 10^9 N
Explanation: We have considered the total charge for each coin , this is the total atoms x 29 electrons for cooper and multiplier by electron charge, the total charge for each coin is 0,464 C
Finally we use the Coulomb law,
F=k Q/ (r)^2