The work done is B. 
Explanation:
The work done by a force on an object is given by

where
F is the magnitude of the force
d is the displacement of the object
is the angle between the direction of the force and of the displacement
For the boat in this problem, we have:
F = 250 N (force applied)
d = 50 m (displacement)

Substituting, we find the work done:

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Answer:
40.92 m/s
Explanation:
The computation is shown below:
Ek = 1 ÷2mv²...............................(1)
v = √(2Ek/m).......................... (2)
Here EK denotes kinetic energy
m denotes mass
v denotes velocity
Given that
m = 0.25kg and Ek = 209.3J
So,
v = √(2×209.3 ÷0.25)
= √1674.4
= 40.92 m/s
Answer:
his acceleration rate is -0.00186 m/s²
Explanation:
Given;
initial position of the car, x₀ = 100 miles = 160, 900 m ( 1 mile = 1609 m)
time of motion, t₀ = 60 minutes = 60 mins x 60 s = 3,600 s
final position of the car, x₁ = 150 miles = 241,350 m
time of motion, t₁ = 100 minutes = 100 mins x 60 s = 6,000 s
The initial velocity is calculated as;
u = 160, 900 m / 3,600 s
u = 44.694 m/s
The final velocity is calculated as;
v = 241,350 m / 6,000 s
v = 40.225 m/s
The acceleration is calculated as;

Therefore, his acceleration rate is -0.00186 m/s²
Answer:
Force can also be described intuitively as a push or a pull. ... It is measured in the SI unit of newtons and represented by the symbol F. The original form of Newton's second law states that the net force acting upon an object is equal to the rate at which its momentum changes with time.
Explanation:
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