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galina1969 [7]
3 years ago
6

Fast!! Help me!!Subject- Science​

Physics
1 answer:
Archy [21]3 years ago
8 0

Last One.... If Im not Wrong!

Burning of Fossil Fuels, Increase the CO2 And therefore the Green Effect!!

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A scientist spends most of his time observing the night time sky and tracking the orbits of planets. Which branch of physical sc
gulaghasi [49]
Astronomy!!? 
if its wrong do you have choices 

4 0
3 years ago
Which one is it<br> Plz help me :)
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5 I think will be none of the above and 6 could be all of the above

8 0
2 years ago
Linh builds a circuit from the diagram shown. Which bulb could Linh remove from the circuit to make all of the other bulbs stop
LenKa [72]

Answer:

4

Explanation:

In order for the current to continue flowing through the circuit (and for the bulbs to continue shining), there must be a closed path containing the battery where current can flow. Let's see the effect of removing each bulb on the circuit:

- 1: when removing bulb 1 only, the current can still flow through the path battery-bulb 3- bulb 4

- 2: when removing bulb 2 only, the current can still flow through the path battery-bulb 3- bulb 4

- 3: when removing bulb 3 only, the current can still flow through the path battery-bulb 1-bulb 2- bulb 4

- 4: when removing bulb 4 only, the current can no longer flow. In fact, there is no closed path that contains the battery now, so the current will not flow and all the bulbs will stop shining.

4 0
3 years ago
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Lady_Fox [76]
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8 0
3 years ago
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What speed would a proton need to achieve in order to circle Earth 1790 km above the magnetic equator, where the Earth's mag- ne
irinina [24]

Answer:

The velocity is 31.25 m/s and direction is toward west.

Explanation:

Given that,

Distance h= 1790 km = 1.790\times10^{6}\ m

Magnetic field B=4\times10^{-8}\ T

Mass of proton m=1.673\times10^{-21}\ Kg

Radius of earth R =6.38\times10^{6}\ m

Radius of orbit r=R+h

r=6.38\times10^{6}+1.790\times10^{6}

r=8170000\ m

We need to calculate the speed

Using formula of magnetic field

Bvq=\dfrac{mv^2}{r}

v=\dfrac{Bqr}{m}

Put the value into the formula

v=\dfrac{4\times10^{-8}\times1.6\times10^{-19}\times8170000}{1.673\times10^{-21}}

v=31.25\ m/s

Hence, The velocity is 31.25 m/s and direction is toward west.

6 0
3 years ago
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