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Hatshy [7]
3 years ago
10

You want to put a new CD in your car stereo.While driving at 45 mi/h,you look away for 2.0s.What distance (in miles) do you driv

e blind.
Physics
1 answer:
KengaRu [80]3 years ago
3 0

Answer:

You drive 0.025 miles blind (or 132 ft)

Explanation:

(distance) = (speed) x (time)

(distance blind) = (speed) x (time looking for CD)

(distance blind) = (45 mi/hr) x (2 s) x (1/3600 hr/s) = 0.025 miles = 132 ft


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A skater pushes off a wall and skates backward for a few meters before stopping.
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Given two vectors A--> = 4.20 i^+ 7.20 j^ and B--> = 5.70 i^− 2.40 j^ , find the scalar product of the two vectors A-->
Arisa [49]

Answer:

\vec{A}\times \vec{B}=-51.12\hat{k}

\theta=83.2^{\circ}

Explanation:

We are given that

\vec{A}=4.2\hat{i}+7.2\hat{j}

\vec{B}=5.70\hat{i}-2.40\hat{j}

We have to find the scalar product and the  angle between these two vectors

\vec{A}\times \vec{B}=\begin{vmatrix}i&j&k\\4.2&7.2&0\\5.7&-2.4&0\end{vmatrix}

\vec{A}\times \vec{B}=\hat{k}(-10.08-41.04)=-51.12\hatk}\hat{k}

Angle between two vectors is given by

sin\theta=\frac{\mid a\times b\mid}{\mid a\mid \mi b\mid}

Where \theta in degrees

\mid{\vec{A}}\mid=\sqrt{(4.2)^2+(7.2)^2}=8.3

Using formula\mid a\mid=\sqrt{x^2+y^2}

Where x= Coefficient of unit vector i

y=Coefficient of unit vector j

\mid{\vec{B}}\mid=\sqrt{5.7)^2+(-2.4)^2}=6.2

\mid{\vec{A}\times \vec{B}}\mid=\sqrt{(-51.12)^2}=51.12

Using the formula

sin\theta=\frac{51.12}{8.3\times 6.2}=0.993

\theta=sin^{-1}(0.993)=83.2degrees

Hence, the angle between given two vectors=83.2^{\circ}

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