Given required solution
M=10kg W=? W=Fd
v=5.0m/s F=mg
t=2.40s =10*10=100N
S=VT
=5m/s*2.4s
=12m
so W=12*100
W=1200J
Answer:
Abdominal
Sitting up, postural alignment
Biceps
Lifting, pulling
Deltoids
Overhead lifting
Erector Spinae
Postural alignment
Gastronemius & Soleus
Push off for walking, standing on tiptoes
Gluteus
Climbing stairs, walking, standing up
Hamstrings
Walking
Latissimus Dorsi & Rhomboids
Postural alignment, pulling open a door
Obliques
Rotation and side flexion of body
Pectoralis
Push up, pull up, bench press
Quadriceps
Climbing stairs, walking, standing up
Trapezius
Moves head sideways
Triceps
Pushing
God bless you. Because my soul almost left my body when i had to do this.
Answer;
It's about acceleration, right?
To solve the problem it is necessary to apply the concepts related to Force of Friction and Tension between the two bodies.
In this way,
The total mass of the cars would be,


Therefore the friction force at 29Km / h would be,




In this way the tension exerts between first car and locomotive is,



Therefore the tension in the coupling between the car and the locomotive is 