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sveta [45]
3 years ago
5

What is an example of a invertebrate that doesn’t have an exoskeleton?

Physics
2 answers:
Tatiana [17]3 years ago
5 0

<em><u>Invertebrat</u></em><em><u>e</u></em><em><u> </u></em><em><u>means</u></em><em><u> </u></em><em><u>those</u></em><em><u> </u></em><em><u>organism</u></em><em><u> </u></em><em><u>which</u></em><em><u> </u></em><em><u>doesnot</u></em><em><u> </u></em><em><u>have</u></em><em><u> </u></em><em><u>backbone</u></em><em><u> </u></em><em><u>in</u></em><em><u> </u></em><em><u>their</u></em><em><u> </u></em><em><u>body</u></em><em><u> </u></em><em><u>.</u></em><em><u>Some</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>t</u></em><em><u>he</u></em><em><u> </u></em><em><u>examples</u></em><em><u> </u></em><em><u>are</u></em><em><u>:</u></em>

<em><u>1</u></em><em><u>.</u></em><em><u>S</u></em><em><u>p</u></em><em><u>i</u></em><em><u>d</u></em><em><u>e</u></em><em><u>r</u></em>

<em><u>2</u></em><em><u>.</u></em><em><u>e</u></em><em><u>a</u></em><em><u>r</u></em><em><u>t</u></em><em><u>h</u></em><em><u>w</u></em><em><u>o</u></em><em><u>r</u></em><em><u>m</u></em>

<em><u>3</u></em><em><u>.</u></em><em><u>S</u></em><em><u>t</u></em><em><u>a</u></em><em><u>r</u></em><em><u>f</u></em><em><u>i</u></em><em><u>s</u></em><em><u>h</u></em>

<em><u>4</u></em><em><u>.</u></em><em><u>S</u></em><em><u>e</u></em><em><u>a</u></em><em><u> </u></em><em><u>urchins</u></em><em><u>.</u></em>

<em><u>hope</u></em><em><u> </u></em><em><u>this</u></em><em><u> </u></em><em><u>will</u></em><em><u> </u></em><em><u>help</u></em><em><u> </u></em><em><u>u</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>lot</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

wel3 years ago
5 0
Jellyfish,slugs,worms
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2 years ago
In a fast-pitch softball game the pitcher is impressive to watch, as she delivers a pitch by rapidly whirling her arm around so
svetlana [45]

Answer:

(a). The magnitude of the total acceleration of the ball is 239.97 m/s².

(b). The angle of the total acceleration relative to the radial direction is 11.0°

Explanation:

Given that,

Radius of the circle = 0.681 m

Angular acceleration = 67.7 rad/s²

Angular speed =18.6 rad/s

We need to calculate the centripetal acceleration of the ball

Using formula of centripetal acceleration

a_{c}=\omega^2\times r

Put the value into the formula

a_{c}=(18.6)^2\times0.681

a_{c}=235.5\ m/s^2

We need to calculate the tangential acceleration of the ball

Using formula of tangential acceleration

a_{t}=r\alpha

Put the value into the formula

a_{t}=0.681\times67.7

a_{t}=46.104\ m/s^2

(a). We need to calculate the magnitude of the total acceleration of the ball

Using formula of total acceleration

a=\sqrt{a_{c}^2+a_{t}^2}

Put the value into the formula

a=\sqrt{(235.5)^2+(46.104)^2}

a=239.97\ m/s^2

(b). We need to calculate the angle of the total acceleration relative to the radial direction

Using formula of the direction

\theat=\tan^{-1}(\dfrac{a_{t}}{a_{c}})

Put the value into the formula

\theta=\tan^{-1}(\dfrac{46.104}{235.5})

\theta=11.0^{\circ}

Hence, (a). The magnitude of the total acceleration of the ball is 239.97 m/s².

(b). The angle of the total acceleration relative to the radial direction is 11.0°

5 0
3 years ago
Can y’all help me pleaseeee
mart [117]
it would still be 5
8 0
3 years ago
Read 2 more answers
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