An ant sits on a cd at a distance of 17 cm from the center. If it sits there for 42
1 answer:
Answer:
a) N = 8.54[rev]; b) v = 21.73 [m/s]; c) T = 4.918[s]; d) 12.2[rev/min]
Explanation:
We know that the arc length is calculated by the following expression:
L = α * r
where:
r = radius = 17 [cm] or 0.17 [m]
α = 360° or 2*pi [rad] = 6.283 [rad]
L = (6.283*0.17) = 1.068 [m] = 106.81 [cm] is the distance travelled in one revolution of the CD
a) N = number of revolutions
N = 913 / 106.81
N = 8.54 [rev]
b ) The speed can be calculated by the following expression:
v = d/t
Where:
d = distance = 913[cm]
t = time = 42[sec]
v = 913/42 = 21.73 [cm/s]
c)
We have the number of revolutions and the time therefore we can calculate the number of revolutions per second
w = 8.54 / 42 =0.2033 [rev/s]
And we know that the period is the reciprocal of the time
T = 1 / 0.2033
T = 4.918 [s]
d )
We need to convert from [rev/s] into [rev/min]
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Answer:
The total momentum of the system before the collision is 0.0325 kg-m/s due east direction.
Explanation:
Given that,
Mass of the cart, m = 250 g = 0.25 kg
Initial velocity of the cart, u = 0.31 m/s (due right)
Mass of another cart, m' = 500 g = 0.5 kg
Initial velocity of the another cart u' = -0.22 m/s (due left)
Let p is the total momentum of the system before the collision. It is given by :
So, the total momentum of the system before the collision is 0.0325 kg-m/s due east direction.
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Answer:
Apparent depth = 45 cm
Explanation:
The refractive index of water in a pool, n = 4/3
Real depth, d = 60 cm
We need to find its apparent depth when viewed vertically through air. The ratio of real depth to the apparent depth is equal to the refractive index of the material. Let the apparent depth is d'. So,
So, the apparent depth is 45 cm.