Question

An egg is thrown nearly vertically upward from a point near the cornice of a tall building. It just misses the cornice on the way down and passes a point a distance 46.0 m below its starting point at a time 5.00 s after it leaves the thrower's hand. Air resistance may be ignored.
A. What is the initial speed of the egg? v = ______m/sB. How high does it rise above its starting point? h = ______ mC. What is the magnitude of its velocity at the highest point? v = ________ m/sD. What is the magnitude of its acceleration at the highest point? a = ______ m/s^2

Answer 1

Answer:

15.325 m/s

11.9702153415 m

0

9.81 m/s²

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

g = Acceleration due to gravity = 9.81 m/s² = a

$s=ut+\frac{1}{2}at^2\\\Rightarrow u=\dfrac{s-\frac{1}{2}at^2}{t}\\\Rightarrow u=\dfrac{-46-\frac{1}{2}\times -9.81\times 5^2}{5}\\\Rightarrow u=15.325\ m/s$

The initial velocity of the egg is 15.325 m/s

$v^2-u^2=2as\\\Rightarrow s=\dfrac{v^2-u^2}{2a}\\\Rightarrow s=\dfrac{0^2-15.325^2}{2\times -9.81}\\\Rightarrow s=11.9702153415\ m$

The maximum height is 11.9702153415 m

At the highest point velocity is zero.

Magnitude of acceleration on a freely falling body is always g = 9.81 m/s²