How are energy and temperature related?

The friends start by discussing what they know with respect to electric and magnetic fields. Alexa mentions several differences

Sveta_85 [38]

Answer:

A. "The electric force vector is along the direction of the electric field, whereas the magnetic force vector is perpendicular to the magnetic field."

D. "The kinetic energy of a charged particle moving in an electric field is not altered, whereas the kinetic energy of a charged particle moving in a magnetic field is either increased or decreased, depending on the direction of motion."

Explanation:

Electric fields originate from voltage differences, the higher the voltage, the stronger the resulting field. Magnetic fields originate from electric currents, a stronger current results in a stronger field. An electric field exists even if there is no current. When there is current, the magnitude of the magnetic field will change with power consumption, but the strength of the electric field will remain the same.

8 0

3 years ago

Heat always travels from

Monica [59]

Answer:

from hot toward cold. Heat moves naturally by any of three means. The processes are known as conduction, convection, and radiation. Sometimes more than one may occur at the same time.

Explanation:

4 0

3 years ago

An electron is initially moving at 1.4 x 107 m/s. It moves 3.5 m in the direction of a uniform electric field of magnitude 120 N

algol13

Answer:

K.E = 15.57 x 10⁻¹⁷ J

Explanation:

First, we find the acceleration of the electron by using the formula of electric field:

E = F/q

F = Eq

but, from Newton's 2nd Law:

F = ma

Comparing both equations, we get:

ma = Eq

a = Eq/m

where,

E = electric field intensity = 120 N/C

q = charge of electron = 1.6 x 10⁻¹⁹ C

m = Mass of electron = 9.1 x 10⁻³¹ kg

Therefore,

a = (120 N/C)(1.6 x 10⁻¹⁹ C)/(9.1 x 10⁻³¹ kg)

a = 2.11 x 10¹³ m/s²

Now, we need to find the final velocity of the electron. Using 3rd equation of motion:

2as = Vf² - Vi²

where,

Vf = Final Velocity = ?

Vi = Initial Velocity = 1.4 x 10⁷ m/s

s = distance = 3.5 m

Therefore,

(2)(2.11 x 10¹³ m/s²)(3.5 m) = Vf² - (1.4 x 10⁷)²

Vf = √(1.477 x 10¹⁴ m²/s² + 1.96 x 10¹⁴ m²/s²)

Vf = 1.85 x 10⁷ m/s

Now, we find the kinetic energy of electron at the end of the motion:

K.E = (0.5)(m)(Vf)²

K.E = (0.5)(9.1 x 10⁻³¹ kg)(1.85 x 10⁷ m/s)²

4 0

3 years ago

If an object on a horizontal frictionless surface is attached to a spring, displaced, and then released, it will oscillate. If i

Blababa [14]

Explanation:

An object is attached to the spring and then released. It begins to oscillate. If it is displaced a distance 0.125 m from its equilibrium position and released with zero initial speed. The amplitude of a wave is the maximum displacement of the particle. So, its amplitude is 0.125 m.

After 0.800 seconds, its displacement is found to be a distance 0.125 m on the opposite side. The time period will be, $t=2\times 0.8=1.6\ s$

We know that the relation between the time period and the time period is given by :

$f=\dfrac{1}{t}$

$f=\dfrac{1}{1.6}$

f = 0.625 Hz

So, the frequency of the object is 0.625 Hz. Hence, this is the required solution.

6 0

3 years ago

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lyudmila [28]

Answer:

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5 0

4 years ago