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belka [17]
2 years ago
11

How many solutions does this equation have? a+3+2a=-1+3a+4

Mathematics
1 answer:
Flura [38]2 years ago
6 0
Let's start by cleaning up this equation to make it easier to read by putting all the variables on one side and everything else on the other side using subtraction and addition. Then simplify.
1) Original equation 
<span>a + 3 + 2a = -1 + 3a + 4

2) Subtract 3 from both sides
a + 2a = -3 - 1 + 3a + 4

3) Subtract 3a from both sides
a + 2a - 3a = -3 - 1 + 4

4) Simplify
3a - 3a = -4 + 4
0 = 0

Since 0 = 0 is always true, this equation as an unlimited number of solutions. No matter what you put in for the variable a, it will all cancel out, and you'll get 0 = 0!

------

Answer: Infinite number of solutions

</span>
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What is the 28th term of the arithmetic sequence with a 1 = 4 and d= -2
Amiraneli [1.4K]

Answer:

Step-by-step explanation:

tn = a + (n-1)*d

t28 = 4 +   (27)*-2     27 because 27 = 28 - 1

t28  = 4 + - 54

t28 = 4 - 54

t28 = - 50      

4 0
3 years ago
Tina, Sijil, Kia, vinayash Alisha and shifa are playing game by forming two teams. Three players in each team how many different
IgorC [24]

Answer:

20

Step-by-step explanation:

GIVEN: Tina, Sijil, Kia, vinayash Alisha and shifa are playing game by forming two teams Three players in each team.

TO FIND: how many different ways can they be put into two teams of three players.

SOLUTION:

Total number of players =6

total teams to be formed =2

total players in one team =3

we have to number of ways of selecting 3 players for one team, rest 3 will go in other team.

Total number of ways of selecting 3 players =^6C_3

                                                                      =\frac{6!}{3!3!}

                                                                     =20

Hence total number of different ways in which they can be put into two different teams is 6

5 0
3 years ago
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dolphi86 [110]
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