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kakasveta [241]
4 years ago
11

How can I find the surface area of a right cone with a radius of 6 and slant height of 16

Mathematics
1 answer:
VMariaS [17]4 years ago
3 0
First, you have to calculate the height.
Pythagorean Theorem:
a^2+b^2=c^2
Slant height=c^2
Radius=b^2
So, a^2+6^2=16^2
       a^2+36=256
       a^2=220
       a=14.832397
Surface Area = πr(r+ square root of h^2+r^2)

Surface Area is approximately 414.69
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The percentage 21 is of 28 is equal to the percentage 30 is of 40<br> True?<br> or false?
katovenus [111]

Answer:

False

Step-by-step explanation:

75%

21

28 5.88

21 x 28

100

= 5.88

x 100% = 75%33.3333333333%

28 - 21

21

x 100% = 33.3333333333%

5 0
3 years ago
If y = -6cosx, what is the amplitude?
aniked [119]

 

\displaystyle\bf\\y=-6cos\,x\\\\\textbf{is equivalent to:}\\\\y=6cos(x+\pi)\\\\\textbf{where 6 is the maximum value or amplitude}\\\\\implies~~~\boxed{\bf~amplitude=6}

 

8 0
3 years ago
Change 84% to a fraction
Sauron [17]
21/25 first you would do 84/100 then you would simplify 
3 0
3 years ago
Please help with 3. 4. 5.
Eddi Din [679]
3.
\text{The Triangle Sum Theorem:}\\m\angle A+m\angle B+m\angle C=180^o
x+2x-1+3x+1=180\\6x=180\ \ \ |:6\\x=30
x^o=30^o\\(3x+1)^o=(3\cdot30+1)^o=91^o\\(2x-1)^o=(2\cdot30-1)^o=59^o
4.
r-6+3r-3+5r=180\\9r-9=180\ \ \ |+9\\9r=189\ \ \ |:9\\r=21
(r-6)^o=(21-6)^o=15^o\\(3r-3)^o=(3\cdot21-3)^o=60^o\\(5r)^o=(5\cdot21)^o=105^o
5.
\text{The Exterior Angle Theorem:}\\m\angle CAB+m\angle ABC=m\angle DCB
2g+9g=110\\11g=110\ \ \ |:11\\g=10
m\angle A=2\cdot10^o=20^o\\m\angle ACB=180^o-110^o=70^o\\m\angle B=9\cdot10^o=90^o
4 0
3 years ago
Mr. Jackson is ordering kazoos for his second, third, and fourth grade music classes. The kazoos come in boxes of 8. There are 2
juin [17]
Sorry for the delay with helping you, had to go to work.
The answer is C because the amount of kazoos needed is 1 for every student (so 26 + 24 + 30) and since 8 come in each box, you divide by 8 to get your answer of (26 + 24 + 30) <span>÷ 8
Hope this helped!</span>
7 0
3 years ago
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