How can I find the surface area of a right cone with a radius of 6 and slant height of 16

1 answer:

3 0

First, you have to calculate the height.
Pythagorean Theorem:
a^2+b^2=c^2
Slant height=c^2
Radius=b^2
So, a^2+6^2=16^2
a^2+36=256
a^2=220
a=14.832397
Surface Area = πr(r+ square root of h^2+r^2)

Surface Area is approximately 414.69

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1. we need an equation first. the sum of all angles (108°, n°, 2n°) is equal to 180°. we can depict this with the equation: 108°+2n°+n°=180°

2. now we can solve for the missing variable, n.

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3. now that we know that n=24°, we can solve the value of ∠DOB. we can see that ∠DOB is 2n° which we just plug the number we got for n into the equation. 2*24=48° meaning ∠DOB is 48°

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