Nitrogen Radius = 5.8 x 10⁻¹¹ m
Beryllium Radius = 1.12 x 10⁻¹⁰ m
Let's find the quotient of N/Be :
(5.8x10⁻¹¹)/(1.12x10⁻¹⁰). But 10⁻¹¹/10⁻¹⁰ = 10⁽⁻¹¹⁺¹⁰⁾ = 10⁻¹ = 1/10 = 0.1
→ (5.8/1.12).(0.1) = 0.58/1.12 = 0.518.
Conclusion: the radius of Be is almost double than the radius of N
The answer of t he trapezoid area problem is 112.
The boat travels 501 miles in 3 weeks.
SohCahToa is an acronym for the basic trigonometric functions which are sine, cosine, and tangent. Sine's value comes from the quotient of the opposite side and the hypotenuse. Cosine's value comes from the quotient of the adjacent side and the hypotenuse. Lastly, Tangent is the quotient of the opposite side and the adjacent side.
The independent variable is the one you change to get your dependent variable. in this case, the independent would be the number of quarters you have
