3 years ago

Please help I will reward brainly

Chemistry

1 answer:

ahrayia [7]3 years ago

3 0

It is in the water. The answer would be A.

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Explanation:

The given data is as follows.

n = 2 mol, P = 1 atm, T = 300 K

Q = +34166 J, W= -1216 J (work done against surrounding)

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Relation between internal energy, work and heat is as follows.

Change in internal energy ( $\Delta U$ ) = Q + W

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Also, $\Delta U = n \times C_{v} \times \Delta T$

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32950 J = $3 \times 8.314 J/mol K \times (T_{2} - 300 K)$

$\frac{32950}{24.942} = T_{2} - 300 K$

1321.06 K + 300 K = $T_{2}$

$T_{2}$ = 1621.06 K

Thus, we can conclude that the final temperature of the gas is 1621.06 K.

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