Question

This is the equation for the combustion of propane.

Answer 1

Answer:

B

Explanation:

Reactants are the compounds which reaction produce the products. In general terms this can be expressed symbolically as follows:

reactants -> products

Other phenomena like heat are omitted because are not always present, that is, only compounds are included. Therefore, in this reaction the reactants are C3H8 (propane) and O2 ( oxygen) and the products are CO2 (carbon dioxide) and H2O (water)

Answer 2

Answer:

$\huge \boxed{\mathrm{Option \ B}}$

$\rule[225]{225}{2}$

Explanation:

$\sf C_3 H_8 +O_2 \Rightarrow CO_2 + H_2 O$

Balancing Carbon atoms on the right side,

$\sf C_3 H_8 +O_2 \Rightarrow 3CO_2 + H_2 O$

Balancing Hydrogen atoms on the right side,

$\sf C_3 H_8 +O_2 \Rightarrow 3CO_2 +4 H_2 O$

Balancing Oxygen atoms on the left side,

$\sf C_3 H_8 +5O_2 \Rightarrow 3CO_2 +4 H_2 O$

The reactants are on the left side of the reaction:

$\sf \boxed{\sf C_3 H_8 +O_2} \Rightarrow CO_2 + H_2 O$

Propane and oxygen are the reactants.

The products are on the right side of the reaction:

$\sf C_3 H_8 +O_2 \Rightarrow \boxed{\sf CO_2 + H_2 O}$

Carbon dioxide and water are the products.

$\rule[225]{225}{2}$