Question

Radon-219 decays to radon-218 by releasing... a. a positron b.a muon O c. a neutron O d. an electron O e. a proton

Answer 1

Answer: Option (c) is the correct answer.

Explanation:

A positron is denoted as $^{0}_{+1}e$, a neutron is denoted as $^{1}_{0}n$, an electron is denoted as $^{0}_{-1}e$, and a proton is denoted as $^{1}_{1}p$.

Therefore, when $^{219}Rn$ will decay into $^{218}Rn$ this means there occurs decrease in its mass number. Hence, it means a neutron will be releasing during this reaction.

The reaction will be as follows.

                $^{219}Rn \rightarrow ^{218}Rn + ^{1}_{0}n$