Question

g Green plants use light from the Sun to drive photosynthesis. Photosynthesis is a chemical reaction in which water and carbon dioxide chemically react to form the simple sugar glucose and oxygen gas . What mass of simple sugar glucose is produced by the reaction of 9.51 g of carbon dioxide

Answer 1

Answer:

We will have 6.49 grams of glucose

Explanation:

Step 1: Data given

water = H2O

carbon dioxide = CO2

glucose = C6H12O6

oxygen = O2

mass of carbon dioxide (CO2) = 9.51 grams

Molar mass of CO2 = 44.01 g/mol

Molar mass of glucose = 180.156 g/mol

Step 2: The balanced equation

6CO2 + 6H2O → C6H12O6 + 6O2

Step 3: Calculate moles CO2

Moles CO2 = mass CO2 / molar mass CO2

Moles CO2 = 9.51 grams / 44.01 g/mol

Moles CO2 = 0.216 moles

Step 4: Calculate moles glucose

For 6 moles CO2 we need 6 moles H2O to produce 1 mol glucose and 6 moles O2

For 0.216 moles CO2 we'll have 0.216/6 = 0.036 moles glucose

Step 5: Calculate mass glucose

Mass glucose = moles glucose * molar mass glucose

Mass glucose = 0.036 moles * 180.156 g/mol

Mass glucose = 6.49 grams

We will have 6.49 grams of glucose

Answer 2

Answer:

6.49g

Explanation:

Let's consider the balanced reaction for photosynthesis.

6 CO₂ + 6 H₂O = C₆H₁₂O₆ + 6 O₂

We can establish the following relations:

• 1 mole of CO₂ has a mass of 44.01 g (MW 44.01)
• The molar ratio of CO₂ to C₆H₁₂O₆ is 6:1.
• 1 mole of C₆H₁₂O₆ has a mass of 180.16 g/mol.

The mass of glucose produced by the reaction of 9.51 g of carbon dioxide is:

$9.51gCO_2 \times \frac{1molCO_2}{44.01gCO_2} \times \frac{1molGlucose}{6molCO_2} \times \frac{180.16gGlucose}{1molGlucose} = 6.49g Glucose$