23.01 g of zinc (Zn)
Explanation:
We have the following chemical reaction:
3 Zn + 2 H₃PO₄ = 3 H₂ + Zn₃(PO₄)₂
number of moles = mass / molar weight
number of moles of phosphoric acid = 23.1 / 98 = 0.236 moles
Taking in account the chemical reaction, we devise the following reasoning:
if 2 moles of H₃PO₄ are reacting with 3 moles of Zn
then 0.236 moles of H₃PO₄ are reacting with X moles of Zn
X = (0.236 × 3) / 2 = 0.354 moles of Zn
mass = number of moles × molar weight
mass of Zn = 0.354 × 65 = 23.01 g
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Answer:
The molarity of the formed CaBr2 solution is 0.48 M
Explanation:
Step 1: Data given
Number of moles CaBr2 = 0.72 moles
Volume of water = 1.50 L
Step 2: Calculate the molarity of the solution
Molarity of CaBr2 solution = moles CaBr2 / volume water
Molarity of CaBr2 solution = 0.72 moles / 1.50 L
Molarity of CaBr2 solution = 0.48 mol / = 0.48 M
The molarity of the formed CaBr2 solution is 0.48 M
Both of you are overlooking a pretty big component of the question...the Group I cation isn't being dissociated into water. We're testing the solubility of the cation when mixed with HCl. And this IS a legitimate question, seeing as our lab manual is the one asking.
<span>By the way, the answer you're looking for is "Because Group I cations have insoluble chlorides". </span>
<span>"In order...to distinguish cation Group I, one adds HCl to a sample. If a Group I cation is present in the sample, a precipitate will form." </span>
Hydrolysis of Methyl Benzoate yields Benzoic Acid and Methanol. This reaction is also called as
Tranesterification (reverse of esterification). Acid in this reaction protonates the carbonyl oxygen, resulting in increasing electrophillic character of carbonyl carbon. Water acts as a nucleophile and methoxide leaves as a good leaving group.
Mechanism is shown below,
<span>Scientific conclusions are based on scientific evidence</span>