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scZoUnD [109]
3 years ago
15

How does the light source readout differ from the x-ray readout in the gizmo??

Chemistry
1 answer:
Fantom [35]3 years ago
3 0
X-rays differ from the light source readout in terms of the intensity and the possible damage that can be obtained from the two radiation types. The light source readout is more damaging than the X-rays readout in the gizmo. Therefore, precaution is required when handling the light source readout in the gizmo.
You might be interested in
Which of the following properties of a protein is least likely to be affected by changes in pH? Tertiary structure Primary struc
chubhunter [2.5K]

Answer:

Primary structure is the correct answer.

Explanation:

  • The primary structure is the simple level of protein structure.
  • Primary structure is a basic amino acids sequences in a protein.
  • In the primary structure, amino acids are attached together by a covalent bond.
  • Primary structure is when the amino acids are joined together with peptide bonds to produce polypeptide chains
  • Changes in pH are least likely to change the amino acid sequence or disrupt peptide bonds.

Explanation:

7 0
3 years ago
What is the velosity of a 72.3 kg jogger with a kinetic energy of 1080.0 J?
Svet_ta [14]

Answer: 5.47m/s

Explanation:

Mass = 72.3kg

K.E = 1080.0J

V =?

K.E = 1 /2MV^2

V^2 = 2K.E /M = (2x1080)/72.3

V = sqrt [(2x1080)/72.3]

V = 5.47m/s

7 0
3 years ago
A sample of CO2 weighing 86.34g contains how many molecules?
irakobra [83]

Answer:

1.181 × 10²⁴ molecules CO₂

General Formulas and Concepts:

<u>Chemistry - Atomic Structure</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Explanation:

<u>Step 1: Define</u>

86.34 g CO₂

<u>Step 2: Identify Conversion</u>

Avogadro's Number

Molar Mass of C - 12.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of CO₂ - 12.01 + 2(16.00) = 44.01 g/mol

<u>Step 3: Convert</u>

<u />86.34 \ g \ CO_2(\frac{1 \ mol \ CO_2}{44.01 \ g \ CO_2} )(\frac{6.022 \cdot 10^{23} \ molecules \ CO_2}{1 \ mol \ CO_2} ) = 1.18141 × 10²⁴ molecules CO₂

<u>Step 4: Check</u>

<em>We are given 4 sig figs. Follow sig fig rules and round.</em>

1.18141 × 10²⁴ molecules CO₂ ≈ 1.181 × 10²⁴ molecules CO₂

4 0
3 years ago
Problem 4
Hunter-Best [27]
<h3>Answer:</h3>

1.93 g

<h3>Explanation:</h3>

<u>We are given;</u>

The chemical equation;

2C₂H₆(g) + 7O₂(g) → 4CO₂(g) + 6H₂O(l) ΔH = -3120 kJ​

We are required to calculate the mass of ethane that would produce 100 kJ of heat.

  • From the equation given;
  • 2 moles of ethane burns to produce 3120 Kilo joules of heat
  • Therefore;

Number of moles that will produce 100 kJ will be;

= (2 × 100 kJ) ÷ 3120 kJ)

= 0.0641 moles

  • But, molar mass of ethane is 30.07 g/mol

Therefore;

Mass of ethane = 0.0641 moles × 30.07 g/mol

                          = 1.927 g

                          = 1.93 g

Thus, the mass of ethane that would produce 100 kJ of heat is 1.93 g

3 0
3 years ago
What was the original element formed moments after the Big Bang? What then created higher order elements?
Semmy [17]
Hydrogen (H) was first, followed by helium (He).
6 0
2 years ago
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