How do you think the bonds between carbon atoms might be different in diamond and graphite?

Chemistry

1 answer:

madreJ [45]3 years ago

7 0

They are arranged differently, in diamonds they are interconnected bonds and in graphite they are arranged as sheets.

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One isotope of a metallic element has the mass number 67 and 37 neutrons in the nucleus. The cation derived from the isotope has

Anuta_ua [19.1K]

No. Of protons = mass no. - no. Of neutrons
No. Of protons = 67 - 37
= 30
No. Of electrons = 28

Zinc will have 30 protons and 28 electrons. So, it will have +2 charge

Symbol - Zn^+2

6 0

3 years ago

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What was George Washington Caver professional information

Sedbober [7]

Explanation:

George Washington Carver was born enslaved and went on to become one of the most prominent scientists and inventors of his time, as well as a teacher at the Tuskegee Institute. Carver devised over 100 products using one major crop — the peanut — including dyes, plastics and gasoline.

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3 years ago

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Ionic bonding occurs when ______ atom donates one or more _______ to a _______ atom

Svetllana [295]

Answer:

ionic bonding occurs when unstable atoms donates one or more valence electrons to a unstable atom

Explanation:

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3 years ago

Formic acid, which is a component of insect venom, has a ka = 1.8 ´ 10-4. what is the [h3o+] in a solution that is initially 0.1

scoray [572]

Answer is: concentratio of H₃O⁺ ions is 4.2·10⁻³ M.
Chemical reaction: HCOOH(aq) + H₂O(l) ⇄ HCOO⁻(aq) + H₃O⁺(aq).
c(HCOOH) = 0,1 M.
[H₃O⁺] = [HCOO⁻] = x.
[HCOOH] = 0,1 M - x.
Ka = [H₃O⁺] · [HCOO⁻] / [HCOOH].
0,00018 = x² / (0,1 M - x).
Solve quadratic equation: x = [H₃O⁺] = 0,0042 M.

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3 years ago

Indicate what happens to the concentration of Pb2+ in each half cell

Taya2010 [7]

Answer:

Your questions requires diagrams of the cell to get which one is on the left or right. However, see the attached file below

The correct answer is (d) the left half-cell will decrease in concentration; and the right half-cell will increase in concentration.

Explanation:

The concentration of the Pb2+ increases in the oxidation half cell while the concentration of the Pb2+ decreases in the reduction half cell during the reaction.

In the Left Beaker (Left half cell), their is less concentration

Pb(s) ---> Pb2+(aq) + 2 e- Concentration of Pb2+(aq) increase ; Electrons going out from this side

In the Right Beaker (right half cell), their is more concentration

Pb2+(aq) + 2 e- ---> Pb(s) Concentration of Pb2+(aq) decrease ; Electrons coming in to this side

Electrons will flow from Left to Right direction.

3 0

3 years ago