first we have to find the empirical formula of the compound
empirical formula is the simplest ratio of whole numbers of components making up a compound
for 100 g of the compound
N O
mass 46.7 g 53.3 g
number of 46.7 g/ 14 g/mol 53.3 g/ 16 g/mol
moles = 3.34 mol = 3.33 mol
divide by the least number of moles
3.34/3.33 = 1.00 3.33/ 3,33 = 1.00
therefore number of atoms are
N - 1
O - 1
empirical formula is - NO
mass of empirical unit - 14 g/mol + 16 g/mol = 30 g
molecular formula is actual composition of elements in the compound
molecular mass - 60.01 g/mol
number of empirical units = molecular mass / empirical unit mass
= 60.01 g/mol / 30 g = 2
there are 2 empirical units
2(NO)
molecular formula = N₂O₂
The mass of iron (III) oxide (Fe2O3) : 85.12 g
<h3>Further explanation</h3>
Given
3.20x10²³ formula units
Required
The mass
Solution
1 mole = 6.02.10²³ particles
Can be formulated :
N = n x No
N = number of particles
n = mol
No = 6.02.10²³ = Avogadro's number
mol of Fe₂O₃ :

mass of Fe₂O₃ (MW=160 g/mol)

H2SO4 or hydrogen sulfate is an acid and NaOH or sodium hydroxide is a base or an alkali. The reaction between an acid and a base or alkali produces a salt and water. The reaction between these substances is shown below:
H2SO4 (aq) + 2NaOH (aq)------>2H20 (L) + Na2SO4 (aq). The salt produced in this reaction is sodium sulfate.
<u>Answer:</u> The percentage abundance of
and
isotopes are 75.77% and 24.23% respectively.
<u>Explanation:</u>
Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.
Formula used to calculate average atomic mass follows:
.....(1)
Let the fractional abundance of
isotope be 'x'. So, fractional abundance of
isotope will be '1 - x'
- <u>For
isotope:</u>
Mass of
isotope = 34.9689 amu
Fractional abundance of
isotope = x
- <u>For
isotope:</u>
Mass of
isotope = 36.9659 amu
Fractional abundance of
isotope = 1 - x
- Average atomic mass of chlorine = 35.4527 amu
Putting values in equation 1, we get:
![35.4527=[(34.9689\times x)+(36.9659\times (1-x))]\\\\x=0.7577](https://tex.z-dn.net/?f=35.4527%3D%5B%2834.9689%5Ctimes%20x%29%2B%2836.9659%5Ctimes%20%281-x%29%29%5D%5C%5C%5C%5Cx%3D0.7577)
Percentage abundance of
isotope = 
Percentage abundance of
isotope = 
Hence, the percentage abundance of
and
isotopes are 75.77% and 24.23% respectively.
Answer:
Germanium.
Explanation:
In a neutral atom: the number of protons = the number of electrons.
Atomic number of a neutral atom = number of electrons = number of protons.
- Phosphorous is an element with atomic number 15 and thus contains 15 electrons and 15 protons.
- Cobalt is an element with atomic number 27 and thus contains 27 electrons and 27 protons.
- <em>Germanium is an element with atomic number 32 and thus contains 32 electrons and 32 protons.</em>
<em></em>
- Sulfur is an element with atomic number 16 and thus contains 16 electrons and 16 protons.