As the vibration of molecules increases, the ____

Which form of oxygen (solid,liquid or gas) would have the highest temperature

ElenaW [278]

Answer:

drip drip water splash (gas)

Explanation:

8 0

3 years ago

Sodium-potassium pumps are examples of what type of cellular transport?

Dmitrij [34]

Answer:

Active transport

Explanation:

Sodium-potassium pumps are examples of Active type of cellular transport. Sodium potassium pump exchanges sodium ions from potassium ions through the plasma membrane of animal cells.

Whereas Active transport can be defined as movement of ions and molecules across a cell membrane to the region of higher concentration with the help of enzymes and energy.

5 0

4 years ago

For the reaction 2kclo3(s)→2kcl(s)+3o2(g) calculate how many grams of oxygen form when each quantity of reactant completely reac

barxatty [35]

First, we need to get the molar mass of:

KClO3 = 39.1 + 35.5 + 3*16 = 122.6 g/mol

KCl =39.1 + 35.5 = 74.6 g/mol

O2 = 16*2 = 32 g/mol

From the given equation we can see that:

every 2 moles of KClO3 gives 3 moles of O2

when mass = moles * molar mass

∴ the mass of KClO3 = (2mol of KClO3*122.6g/mol) = 245.2 g

and the mass of O2 then = 3 mol * 32g/mol = 96 g

so, 245.2 g of KClO3 gives 96 g of O2

A) 2.72 g of KClO3:

when 245.2 KClO3 gives → 96 g O2

2.72 g KClO3 gives → X

X = 2.72 g KClO3 * 96 g O2/245.2 KClO3

= 1.06 g of O2

B) 0.361 g KClO3:

when 245.2 g KClO3 gives → 96 g O2

0.361 g KClO3 gives → X

∴ X = 0.361g KClO3 * 96 g / 245.2 g

= 0.141 g of O2

C) 83.6 Kg KClO3:

when 245.2 g KClO3 gives → 96 g O2

83.6 Kg KClO3 gives → X

∴X = 83.6 Kg* 96 g O2 /245.2 g KClO3

= 32.7 Kg of O2

D) 22.4 mg of KClO3:

when 245.2 g KClO3 gives → 96 g O2

22.4 mg KClO3 gives → X

∴X = 22.4 mg * 96 g O2 / 245.2 g KClO3

= 8.8 mg of O2

7 0

4 years ago

Finding energy and wavelength?

deff fn [24]

The equation is
W = C/F
W= 3.00 x 10^8 m/sec
——————————
6.165 x 10^14 Hz
W= 4.87 x 10^-7 m

Energy is
E=hF
E= (6.626 x 10^-34 Jxsec )(6.165 x 10^14 Hz)
E= 4.085 x 10^-19 J

3 0

3 years ago

Upon dissolving in , undergoes a disproportionation reaction according to the following unbalanced equation: This disproportiona

pychu [463]

Answer:

The question in the narrative seems not to be complete because the unbalanced equation was not given and the values of the second(s) and chemical dissolved was also not given.

Kindly find the complete question below and if you feel the question is still correct, the solution provided is still implies but without the values inserted.

Correct Question:

Upon dissolving InCl(s) in HCl , In(aq) undergoes a disproportionation reaction according to the following unbalanced equation:

In ⁺ (aq) → In(s) → In³⁺ (aq)

This disproportionation follows first-order kinetics with a half-life of 667s. What is the concentration of In⁺ (aq) after 1.25 h if the initial solution of In⁺ (aq) was prepared by dissolving 2.38 g InCl(s) in dilute HCl to make 5.00 x 10² mL of solution? What mass of In(s) is formed after 1.25h?

Solution / Explanation:

Given half life of In⁺ at 66.7 s,

We recall the formula used in claculating the rate of constant for the first oreder reactin as :

K = 0.693 / t₁÷2,

Noting that:

t₁÷2 = half life

and K= rate constant

Therefore, if we replace the value of t₁÷2 in the formular above,

We have,

K = 0.693 / 667s

K = 0.00 /s

Now, if we recall the mass of InCl(s) as 2.38g,

Volume of dilute HCl = 500 mL,

and the molar mass of InCl(s) - 150.271 g/mol,

The number of moles is then calculated using the formular:

Number of moles: = Given Mass/Molar Mass

Now replacing the given values of given mass and the molar mass in the above formular,

= 2.38g / 150.271g/mol

= 0.0158 mol

Volume of diluted 500 mL.

Recalling also that we need to convert from mL into Liters

Therefore, 1mL = 10⁻³L

Therefore,

500mL = (500 X 10⁻³)L

0.5 L

Now, the molarrity of In⁺ (aq) is calculated using

morality of In⁺ (aq) = moles of In⁺ (aq)/volume of solution

= 0.0158/0.5L

=0.0316M (This is the initial concentration of In⁺ (aq))

The time of the reaction is 1.25h

There is 3600s in one hour

1.25h = 1.25 x 3600

= 4500s

7 0

3 years ago

As the vibration of molecules increases, the _____ of the substance increases.