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3 years ago

Chemistry gcse

Chemistry

1 answer:

mart [117]3 years ago

8 0

Yes, anything with carbonate, hydrogen carbonate (bicarbonate) at the end is a carbonate.

Examples:NaHCO3 (Sodium hydrogen carbonate or Sodium bicarbonate)Na2CO3 (Sodium carbonate)

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Match the theoretical motions of particles with their associated phases. Solid, Gas, Liquid. 1. oscillation about a fixed point

viktelen [127]

The correct combination of theoretical motions of particles with their associated phases is given below:

1) Solid : oscillation about a fixed point . Because solids do vibrate (atoms/molecules of a solid oscillate around their mean positions)
2) Gas : translation, vibration, rotation. The gas molecules are free to rotate, oscillate & vibrate. 
3) Liquid: rotation and vibration. The liquid molecules are free to rotate & vibrate.

A more clear pictures (at atomic & molecular level is shown below):

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3 years ago

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Fermium-253 has a half-life of 0.334 seconds. How long will it take, in seconds, for a 96 atom sample to decay to 3 atoms?

iris [78.8K]

Answer:3.34 seconds

Explanation:

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3 years ago

How many grams of carbon dioxide are produced to react with 0.980 grams of Fe3O4?

NeX [460]

Answer:

0.72g of Co2

Explanation:

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3 years ago

Consider these three titrations: (i) the titration of 25.0 mL of a 0.100 M monoprotic weak acid with 0.100 M NaOH (ii) the titra

Setler79 [48]

Complete Question:

Consider these three titrations: (i) the titration of 25.0 mL of a 0.100 M monoprotic weak acid with 0.100 M NaOH (ii) the titration of 25.0 mL of a 0.100 M diprotic weak acid with 0.100 M NaOH (iii) the titration of 25.0 mL of a 0.100 M strong acid with 0.100 M NaOH. Which statement is most likely to be true?

(a) All three titrations require the same volume of NaOH to reach their first equivalence point.

(b) All three titrations have the same initial pH.

Answer:

(a) All three titrations require the same volume of NaOH to reach their first equivalence point.

Explanation:

(i) the titration of 25.0 mL of a 0.100 M monoprotic weak acid with 0.100 M NaOH

number of moles of acid = $\frac{25}{1000} dm^{3} * 0.1 M$ = 0.0025 moles

ii) the titration of 25.0 mL of a 0.100 M diprotic weak acid with 0.100 M NaOH

number of moles of acid = $\frac{25}{1000} dm^{3} * 0.1 M$ = 0.0025 moles

(iii) the titration of 25.0 mL of a 0.100 M strong acid with 0.100 M NaOH

number of moles of acid = $\frac{25}{1000} dm^{3} * 0.1 M$ = 0.0025 moles

Therefore, all the acids require the same number of moles of NaOH to reach their first equivalence points

Note that the concentration of the base NaOH are also the same, therefore the volume of NaOH required to reach equivalence point would also be the same for all the three titrations.

All three titrations don't have the same initial and equivalence point pH because they all have different acidic properties.

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4 years ago

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A mass of 6.0 grams of carbon contains _______

Ludmilka [50]

Answer:

12.0

Explanation:

i know because i did this in 10th grad

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3 years ago