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Oksi-84 [34.3K]
3 years ago
12

Two litres of an ideal gas at a pressure of 10 atm expands isothermally into a vacuum until its total volume is 10 litres. How m

uch heat is absorbed and how much work is done in the expansion ?
Chemistry
1 answer:
nlexa [21]3 years ago
4 0

Answer:

The work done and heat absorbed are both -8,1 kJ

Explanation:

The work done in an isobaric process is defined as:

W = -P (Vf - Vi)

Where P is pressure ( 10 atm)

Vf = 10 L

Vi = 2 L

Thus, <em>W = -80 atm×L ≡ -8,1 kJ</em>

This is the work done in expansion of the gas.  As the gas remains at the same temperature, there is no change in internal energy doing that all work was absorbed as heat.

I hope it helps!

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3 years ago
Read 2 more answers
An aqueous solution contains the following ions: cl−, ag , pb2 , no−3, and so2−4. More than one precipitate will form. Identify
klasskru [66]

An aqueous solution contains the following ions Cl⁻, Ag⁺, Pb²⁺, NO₃⁻ & SO₄²⁻ and more than one precipitate will form are AgCl, PbCl₂, PbSO₄ & Ag₂SO₄.

<h3>What is precipitate?</h3>

Precipitate is the insoluble compound which is present at the bottom of any chemical reaction in the solid state.

If in an aqueous solution Cl⁻, Ag⁺, Pb²⁺, NO₃⁻ & SO₄²⁻ ions are present then:

  • Compounds AgCl, PbCl₂, PbSO₄ & Ag₂SO₄ are not soluble in water as it is present in the form of precipitate.
  • Pb(NO₃)₂ is fully soluble in water and will not make precipitate.

Hence precipitates are AgCl, PbCl₂, PbSO₄ & Ag₂SO₄.

To know more about precipitates, visit the below link:

brainly.com/question/2437408

#SPJ4

8 0
2 years ago
A 0.98 gram sample of a volatile liquid was heated to 348 k. the gas occupied 265 ml of space at a pressure of 0.95 atm. what is
arlik [135]

Answer:

The molecular weight is Z =  111.2 \ g/mol

Explanation:

From the question we are told that

   The mass of the sample is  m =  0.98 \  g

    The temperature is  T  =  348 K

    The volume which the gas occupied is  V  =  265 \ ml  = 265 *10^{-3} L

     The pressure is  P  =  0.95 \  atm

Generally from the ideal gas equation we have that

       PV  =  n RT

Here n is the number of moles of the gas while the R is the gas constant with value  R  =  0.0821 \ atm \cdot L  \cdot mol^{-1} \cdot K^{-1}

        n = \frac{PV}{ RT}

=>      n = \frac{ 0.95 * 265 *10^{-3} }{   0.0821 * 348}

=>      n = 0.00881 \  mol

Generally the molecular weight is mathematically represented as

          Z =  \frac{m}{n}

=>      Z =  \frac{0.98 }{0.00881}

=>      Z =  111.2 \ g/mol

8 0
3 years ago
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