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3 years ago

The motion of an object will not be changed if

Physics

2 answers:

BartSMP [9]3 years ago

7 0

As long as the motions are balanced there will be no changes

rosijanka [135]3 years ago

4 0

Balanced forces acting on an object cause no change in the motion of the object.

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Which describes the characteristics of a liquid?

Talja [164]

What happens when you pour water in a glass? It takes the shape of the glass. This means that water can't have a fixed shape or volume

5 0

3 years ago

A thin layer of oil of refractive index 1.22 is spread on the surface of water (n = 1.33), If the thickness of the oil is 275 nm

ANTONII [103]

Answer:

6.71×10⁻⁷ m

Explanation:

Using thin film constructive interference formula as:

2×n×t = m×λ

Where,

n is the refractive index of the refracted surface

t is the thickness of the surface

λ is the wavelength

If m =1

Then,

2×n×t = λ

Given that refractive index pf the oil is 1.22

Thickness of the oil = 275 nm

Also, 1 nm = 10⁻⁹ m

Thickness = 275×10⁻⁹ m

So,

Wavelength is :

λ= 2×n×t = 2× 1.22 × 275×10⁻⁹ m = 6.71×10⁻⁷ m

8 0

3 years ago

A large grinding wheel in the shape of a solid cylinder of radius 0.330 m is free to rotate on a frictionless, vertical axle. A

ArbitrLikvidat [17]

Answer:

The mass of the solid cylinder is $m = 1612.5 \ kg$

Explanation:

From the question we are told that

The radius of the grinding wheel is $R = 0.330 \ m$

The tangential force is $F_t = 250 \ N$

The angular acceleration is $\alpha = 0.940 \ rad/s^2$

The torque experienced by the wheel is mathematically represented as

$\tau = I * \alpha$

Where I is the moment of inertia

The torque experienced by the wheel can also be mathematically represented as

$\tau = F_t * r$

substituting values

$\tau = 250 * 0.330$

$\tau = 82.5 \ N\cdot m$

$82.5 = I * \alpha$

$82.5 = I * 0.940$

$I = 87.8 \ kg \cdot m^2$

This moment of inertia can be mathematically evaluated as

$I = \frac{1}{2} * m* r^2$

substituting values

$87.8 = \frac{1}{2} * m* (0.330)^2$

=> $m = 1612.5 \ kg$

5 0

3 years ago

A circular grill of diameter 0.25 m has an emissivity of 0.8. If the surface temperature is maintained at 150°C, determine the r

Schach [20]

Answer:

the required electrical power when the room air and surroundings are at 30°C.= 52.51822 Watt

Explanation:

Power required to maintain the surface temperature at 150°C from 20°C

P= εσA(T^4-t^4)

P= power in watt

ε= emissivity

A= area of surface

T= 150°C= 423 K

t= 20°C= 303K

/sigma= 5.67×10^{-8} watt/m^2K^4

putting vales we get

$= 0.8\times5.67\times10^{-8} \pi\frac{0.25^4}{4}(423^4-303^4)$

P=52.51822 Watt

the required electrical power when the room air and surroundings are at 30°C.= 52.51822 Watt

4 0

2 years ago

What is the acceleration of a 5kg rock that is thrown with a force of 18N?

natita [175]

Answer:

F = m×a

a = F /m

a = 90 m/s²

hope it's helps you

8 0

3 years ago