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romanna [79]
4 years ago
15

The motion of an object will not be changed if

Physics
2 answers:
BartSMP [9]4 years ago
7 0
As long as the motions are balanced there will be no changes
rosijanka [135]4 years ago
4 0
Balanced forces acting on an object <span>cause no </span>change<span> in </span>the motion<span> of the </span>object<span>.</span>
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Rank the ten objects from loudest to softest.
frez [133]
Um what are the ten objects..?
5 0
3 years ago
Two boats are anchored in the harbor, separated by a horizontal distance of 18 m. The boats bob up and down as waves enter the h
sineoko [7]
<h2><u>Given</u>:</h2>

Horizontal distance between two boats = x = 14 m

One boat is at trough, the other is at crest.

As there is no crests between them meaning the boat are next to each other.

Wavelength is the distance between two consecutive crests/troughs = w

The distance between a crest and a trough next to it = w/2

Complete cycles = c = 5

Time taken for c cycles = t = 15 s

Vertical distance between two boats = y = 2.4 m

<h2><u>To find</u>:</h2>

wavelength = w = 2x = 28 m

Amplitude =  A = Displacement from mean to extreme position = y/2 = 1.2 m

Time period for one cycle = T = t/c = 15/5 = 3 s/cycle

frequency = 1/T = 1/3 = 0.33 hertz

speed = wavelength/Period = w/T = 28/3 = 9.33 m/s

4 0
3 years ago
A rocket sled for testing equipment under large accelerations starts at rest and accelerates according to the expression a = (3.
mash [69]

Answer:

9.6 m

Explanation:

This is a  case of motion under variable acceleration . So no law of motion formula will be applicable here. We shall have to integrate the given equation .

a = 3.6 t + 5.6

d²x / dt² = 3.6 t + 5.6

Integrating on both sides

dx /dt = 3.6 t² / 2 + 5.6 t + c

where c is a constant.

dx /dt = 1.8  t²  + 5.6 t + c

when t = 0 , velocity dx /dt is zero

Putting these values in the equation above

0 = 0 +0 + c

c = 0

dx /dt = 1.8  t²  + 5.6 t

Again integrating on both sides

x = 1.8 t³ / 3 + 5.6 x t² /2 + c₁

x = 0.6 t³  + 2.8  t²  + c₁

when t =0,  x = 0

c₁ = 0

x = 0.6 t³  + 2.8  t²  

when t = 1.6

x = .6 x 1.6³ + 2.8 x 1.6²

= 2.4576 + 7.168

= 9.6256

9.6 m

5 0
3 years ago
A 1.3-kg ball is attached to the end of a 0.8-m string to form a pendulum. This pendulum is released from rest with the string h
Natali5045456 [20]

Answer:

2.9 m/s

Explanation:

Momentum will be conserved

Speed of the ball just before collision is

v = √2gh = √(2(9.8)(0.8)) = 3.96 m/s

The initial momentum is 1.3(3.96) = 5.15 kg•m/s

The block takes away momentum of 0.6(2.2) = 1.32 kg•m/s

Leaving the ball with momentum of 5.15 - 1.32 = 3.83 kg•m/s

vf(ball) = 3.83 / 1.3 = 2.946... ≈ 2.9 m/s

3 0
3 years ago
Describe how you can see and feel sound waves
Paraphin [41]

Answer:

Sound is a vibration, or wave, that travels through the air. Sound waves are invisible to our eyes; unless we find a way to make the sound waves move something that we can see. In this activity, your child will use different noise-making objects to cause sound waves and make sand visibly move.

Sound wave can be described by five characteristics: Wavelength, Amplitude, Time-Period, Frequency and Velocity or Speed. The minimum distance in which a sound wave repeats itself is called its wavelength.

Explanation:

When the vibrating air hits your eardrum, it causes your eardrum to vibrate, just as the balloon did. These vibrations are transferred through the tiny bones in your ear to the inner ear. These vibrations are detected by nerves, which send impulses that your brain "hears" as sound.

5 0
3 years ago
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