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romanna [79]
3 years ago
15

The motion of an object will not be changed if

Physics
2 answers:
BartSMP [9]3 years ago
7 0
As long as the motions are balanced there will be no changes
rosijanka [135]3 years ago
4 0
Balanced forces acting on an object <span>cause no </span>change<span> in </span>the motion<span> of the </span>object<span>.</span>
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Shawn and his bike have a total mass of
Soloha48 [4]
Speed = distance / time
Speed = 700m / 792s = 0.88383838m/s

0.5 times mass times velocity^2
0.5 times 52.9 times 0.8..^2
= 20.6619541

Not sure if it is actually correct tho



5 0
3 years ago
What evidence do we have that the halo population of stars are older than other stars in the galaxy?
weeeeeb [17]

Answer:

a.They have a smaller proportion of heavy elements.

Explanation:

As a  star grows old , its metal content becomes low . Our sun is Population I star which means it is very new . Its metal content is 1.4 % . By the term metal we mean any element heavier than helium . Population II stars are older than population I stars . They will have lesser content of metal . Population III are oldest star group which have metal content as less as .015 % .

7 0
3 years ago
10 kg of R-134a fill a 1.115-m^3 rigid container at an initial temperature of -30∘C. The container is then heated until the pres
Sidana [21]

Answer : The final temperature an the initial pressure of gas is, 273.6 K and 177.6 kPa

Explanation :

First we have to calculate the initial pressure of gas.

As we know that, R-134a is 1,1,1,2-Tetrafluoroethane.

Using ideal gas equation:

PV=nRT\\\\PV=\frac{w}{M}RT

where,

P = pressure of gas = ?

V = volume of gas = 1.115m^3

T = temperature of gas = -30^oC=273+(-30)=243K

R = gas constant = 8.314m^3Pa/mole.K

w = mass of gas = 10 kg = 10000 g

M = molar mass of R-134a gas = 102.03 g/mole

Now put all the given values in the ideal gas equation, we get:

P\times 1.115m^3=\frac{10000g}{102.03g/mole}\times (8.314m^3Pa/mole.K)\times (243K)

P=177587.9687Pa=177.6kPa

Thus, the initial pressure of gas is, 177.6 kPa

Now we have to calculate the final temperature of gas.

Gay-Lussac's Law : It is defined as the pressure of the gas is directly proportional to the temperature of the gas at constant volume and number of moles.

P\propto T

or,

\frac{P_1}{T_1}=\frac{P_2}{T_2}

where,

P_1 = initial pressure of gas = 177.6 kPa

P_2 = final pressure of gas = 200 kPa

T_1 = initial temperature of gas = -30^oC=273+(-30)=243K

T_2 = final temperature of gas = ?

Now put all the given values in the above equation, we get:

\frac{177.6kPa}{243K}=\frac{200kPa}{T_2}

T_2=273.6K

Thus, the final temperature an the initial pressure of gas is, 273.6 K and 177.6 kPa

4 0
3 years ago
Determine how would the frequency of the pendulum change if it was taken to the moon by finding the ratio of its frequency on th
andrezito [222]

Answer:

you lady boo

Explanation:

7 0
3 years ago
Why is measurement important?​
Neko [114]

Answer:

Measurement is important so we could measure certain things right. By taking measurements we can have a knowledge of sizes, lengths, widths etc.

Explanation:

3 0
3 years ago
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