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3 years ago

The ____ is the place where position equals zero

Physics

1 answer:

Alexus [3.1K]3 years ago

7 0

The answer to your question is the Origin

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Help what is the answer

Ainat [17]

Answer:

Explanation:

$F=k\dfrac{Q_1Q_2}{r^2}= \\\\(8.99 \times 10^9)\dfrac{(-2\times 10^{-4})(8\times 10^{-4})}{0.3^2}\approx 1.6\times 10^4 N$

Hope this helps!

5 0

3 years ago

All 2023 ariya ac synchronous drive motors produce ____% torque at 0 mph for impressive off-the-line acceleration and smooth cru

Savatey [412]

All 2023 Ariya ac synchronous drive motors produce 100% torque at 0 mph for impressive off-the-line acceleration and smooth cruising.

<h3>How to calculate the torque?</h3>

Mathematically, the torque of an automobile vehicle can be calculated by using this formula:

Torque = Fd

<u>Where:</u>

F is the force.

d is the distance.

Generally, torque is a rotational force which is developed by the crankshaft of an automobile vehicle and its capacity to move at a specific acceleration.

Read more on torque here: brainly.com/question/14839816

#SPJ1

8 0

2 years ago

Two rams run toward each other. One ram has a mass of 49 kg and runs west

olga nikolaevna [1]

Answer: (d)

Explanation:

Given

Mass of the first ram $m_1=49\ kg$

The velocity of this ram is $v_1=-7\ m/s$

Mass of the second ram $m_2=52\ kg$

The velocity of this ram $v_2=9\ m/s$

They combined after the collision

Conserving the momentum

$\Rightarrow m_1v_1+m_2v_2=(m_1+m_2)v\\\Rightarrow 49\times (-7)+52\times (9)=(52+49)v\\\Rightarrow v=\dfrac{125}{101}\ m/s \quad[\text{east}]$

Momentum after the collision will be

$\Rightarrow 101\times \dfrac{125}{101}=125\ kg-m/s\ \text{East}$

Therefore, option (d) is correct

4 0

3 years ago

POR FAVOR AYUDENME A COMLETARLO

Zigmanuir [339]

Answer:

English please?

Explanation:

8 0

3 years ago

A baseball with a mass of 151 g is thrown horizontally with a speed of 39.5 m/s (88 mi/h) at a bat. The ball is in contact with

Oduvanchick [21]

Answer:

the average force exerted on the ball by the bat is 11,613.27 N

Explanation:

Given;

mass of the baseball, m = 151 g = 0.151 kg

initial velocity of the baseball, u = 39.5 m/s

final velocity of the baseball, v = 45.1 m/s

time of action, t = 1.10 ms = 1.10 x 10⁻³ s

The average force exerted on the ball by the bat is calculate as;

$F = ma = \frac{m(v-u)}{t} \\\\F = \frac{0.151(45.1-(-39.5))}{1.10\times 10^{-3}} \\\\F = \frac{0.151(45.1\ +\ 39.5)}{1.10\times 10^{-3}} \\\\F = 11,613.27 \ N$

Therefore, the average force exerted on the ball by the bat is 11,613.27 N

7 0

2 years ago