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timama [110]
3 years ago
8

A cannonball is launched from the ground with 48,279 Joules of kinetic energy. How much gravitational potential energy (GPE) wil

l the cannonball hold when it has reached its highest height? How do you know?
Chemistry
1 answer:
VashaNatasha [74]3 years ago
7 0

Given :

A cannonball is launched from the ground with 48,279 Joules of kinetic energy.

To Find :

What is the gravitational potential energy (GPE) will the cannonball hold when it has reached its highest height .

Solution :

We know , in this given case only one force is applied on the body which is gravitational force .

Now , we also know that gravitational force is a conservative force.

Also , total energy is conserved in system when only conservative force is applied in system .

So , total energy will be conserved .

We know, K.E will be max when P.E is zero i.e on ground .

And P.E will be max at maximum height .

So , K.E_{h=0}=P.E_{h_max}

Therefore , the gravitational potential energy (GPE) will the cannonball hold when it has reached its highest height is 48,279 Joules .

Hence , this is the required solution .

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Answer:

964ug

Explanation:

The problem here involves converting from one unit to another.

 We are to convert from ounces to micrograms.

                                    1ug  = 1 x 10⁻⁶g

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So we first convert to grams from oz then take to ug:

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Ksp of PbBr₂ is 6.60 × 10⁻⁶. The molar solubility of PbBr₂ in pure water is 0.0118M.

Ksp or Solubility Product Constant is an equilibrium constant for the dissociation in an aqueous solution.

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Let the molar solubility be S upon dissociation.

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