All categories

2 years ago

Which is least likely to be reduced? A. Zn^2+ B. Fe^3+ C. Cu^2+ D. Fe^2+

Chemistry

1 answer:

alekssr [168]2 years ago

6 0

A. Zn²⁺

<h3>Further explanation</h3>

Given

Cations of several elements

Required

The least to be reduced

Solution

If we look at the voltaic series:

The electrode which is easier to reduce than the hydrogen (H2) electrode has a positive sign (E red= +) and is located to the right of the voltaic series (right of H)

The electrode which is easier to oxidize than the hydrogen (H2) electrode and is difficult to experience reduction has a negative sign (E red= -) and is located to the left of the voltaic series (left of H)

Or you can look at the standard reduction potential value of the metals in the answer options, and the most negative reduction E° value which will be difficult to reduce.

The Zn metal is located far left of the other metals in the answer choices, so it is the most difficult to reduce

You might be interested in

When something slows it’s acceleration is

Minchanka [31]

Answer:

negative

Explanation:

When something slows down, its acceleration is the opposite of the velocity.

8 0

3 years ago

How to make bread step by step

Sedaia [141]

You slap some dough on to a beach and wait for it to become bread

7 0

3 years ago

N2 + 6e → 2N-3

sveta [45]

Answer:

The correct answer is reduction.

Explanation:

Nitrogen gas reacts with hydrogen gas and get reduced to form ammonia. In this reaction.This is important reaction of atmospheric nitrogen fixation.The reaction is carried out by many nitrogen fixing bacteria such as Azotobacter,Clostridium etc.

N2+3H2+6e- = 2NH3

4 0

3 years ago

Iron(III) oxide and hydrogen react to form iron and water, like this: Fe_2O_3(s) + 3H_2(g) rightarrow 2Fe(s) + 3H_2O(g) At a cer

Sergeeva-Olga [200]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The equilibrium constant is $K_c= 2.8*10^{-4}$

Explanation:

From the question we are told that

The chemical reaction equation is

$Fe_{2} O_{3}_{(s)} + 3H_{2}_{(g)} -----> 2Fe_{(s)} + 3H_{2} O_{(g)}$

The voume of the misture is $V_m = 5.4L$

The molar mass of $Fe_{2} O_{3}_{(s)}$ is a constant with value of $M_{Fe_{2} O_{3}_{(s)} } = 160g/mol$

The molar mass of $H_{2}_{(g)}$ is a constant with value of $H_2 = 2g/mol$

The molar mass of $H_{2}O$ is a constant with value of $H_2O = 18g/mol$

Generally the number of moles is mathematically given as

$No \ of \ moles \ = \frac{mass}{molar\ mass}$

For $Fe_{2} O_{3}_{(s)}$

$No \ of\ moles = \frac{3.54}{160}$

$= 0.022125 \ mols$

For $H_{2}$

$No \ of\ moles = \frac{3.63}{2}$

$= 1.815 \ mols$

For $H_{2}O$

$No \ of\ moles = \frac{2.13}{18}$

$= 0.12 \ mols$

Generally the concentration of a compound is mathematicallyrepresented as

$Concentration = \frac{No \ of \ moles }{Volume }$

For $Fe_{2} O_{3}_{(s)}$

$Concentration[Fe_2 O_3] = \frac{0.222125}{5.4}$

$= 4.10*10^{-3}M$

For $H_{2}$

$Concentration[H_2] = \frac{1.815}{5.4}$

$= 0.336M$

For $H_{2}O$

$Concentration [H_2O] = \frac{0.12}{5.4}$

$= 0.022M$

The equilibrium constant is mathematically represented as

$K_c = \frac{[concentration \ of \ product]}{[concentration \ of \ reactant ]}$

Considering $H_2O \ for \ product$

And $H_2 \ for \ reactant$

At equilibrium the

$K_c = \frac{0.022}{0.336}$

$K_c= 2.8*10^{-4}$

3 0

3 years ago

if multicellular organism came from unicellular organisms, then are all species ralated, why do you think so?

Alenkinab [10]

Answer:

Explanation:

Most people when asked, “What is the equation of a line?”, will answer, “y = mx + b”. This is the

equation of a line in what is called slope-intercept form where “m” is the slope and “b” is the yintercept. So, how do you find the equation of a line? There are several different ways that you can find

the equation of a line. I find the equation of a line everytime by following the same three steps:

Step 1: Find the slope of the line.

Step 2: Use the slope to find the y-intercept.

Step 3: Use steps 1 and 2 to write the answer.

I will explain these steps by looking a several examples. Please understand that there are often several

different ways to complete each math problem, but I have found through the years that students are most

successful when the do problems the same way each and every time they attempt the problem. If you

know a different way to find the answer that is great, but I am going to show how to do the problem one

way and use the same technique everytime I see this problem.

3 0

3 years ago