Answer:
Explanation:
I'm not 100% this is what you want, but here it is:
2
3
13
8
11
A
13
Answer:
The flexural strength of a specimen is = 78.3 M pa
Explanation:
Given data
Height = depth = 5 mm
Width = 10 mm
Length L = 45 mm
Load = 290 N
The flexural strength of a specimen is given by
![\sigma = \frac{3 F L}{2 bd^{2} }](https://tex.z-dn.net/?f=%5Csigma%20%3D%20%5Cfrac%7B3%20F%20L%7D%7B2%20bd%5E%7B2%7D%20%7D)
![\sigma = \frac{3(290)(45)}{2 (10)(5)^{2} }](https://tex.z-dn.net/?f=%5Csigma%20%3D%20%5Cfrac%7B3%28290%29%2845%29%7D%7B2%20%2810%29%285%29%5E%7B2%7D%20%7D)
78.3 M pa
Therefore the flexural strength of a specimen is = 78.3 M pa
Answer:
try to pop it back in good luck im scared for you
Answer:
time = 5.22 hr
Explanation:
Given data:
Energy of battery = 9400 J
Power consumed by three led bulb is 0.5 watt
we know Power is give as
![Power = \frac{ energy}{time}](https://tex.z-dn.net/?f=Power%20%3D%20%5Cfrac%7B%20energy%7D%7Btime%7D)
plugging all value and solve for time
![time = \frac{energy}{power}](https://tex.z-dn.net/?f=time%20%3D%20%5Cfrac%7Benergy%7D%7Bpower%7D)
![time = \frac{9400}{0.5}](https://tex.z-dn.net/?f=time%20%3D%20%5Cfrac%7B9400%7D%7B0.5%7D)
time = 18,800 sec
in hour
1 hour = 3600 sec
therefore in 18,800 sec
![time = \frac{18800}{3600} = 5.22 hr](https://tex.z-dn.net/?f=time%20%3D%20%5Cfrac%7B18800%7D%7B3600%7D%20%3D%205.22%20hr)
Answer:
#include <stdio.h>
void SplitIntoTensOnes(int* tensDigit, int* onesDigit, int DecVal){
*tensDigit = (DecVal / 10) % 10;
*onesDigit = DecVal % 10;
return;
}
int main(void) {
int tensPlace = 0;
int onesPlace = 0;
int userInt = 0;
userInt = 41;
SplitIntoTensOnes(&tensPlace, &onesPlace, userInt);
printf("tensPlace = %d, onesPlace = %d\n", tensPlace, onesPlace);
return 0;
}