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notsponge [240]
3 years ago
5

Early American rockets used an RC circuit to set the time for the rocket to begin re-entry after launch (true story). Assume the

capacitor is initially charged, and then discharge begins at launch, t = 0 (this was when the umbilical connector was disconnected). Further assume the resistor in the RC circuit is 1k Ω, and the control circuit begins re-entry when the voltage drops ~63% or to ~37% of full-scale (i.e. 1 time constant), and re-entry is desired to commence at 5 minutes (i.e. 300 seconds after launch). Calculate the capacitor value required.
Engineering
1 answer:
koban [17]3 years ago
3 0

Answer:

C = 0.3 F

Explanation:

The expression for a voltage in a capacitor with an initial voltage V₀, as a function of time, is given by the following equation:

V= Vo*e^{-t/RC}

When V = =.37*V₀, we have the following expression:

\frac{V}{Vo} = e^{-t/RC} = 0.37

Applying ln to both sides, we have:

\frac{-t}{RC} = ln 0.37 = -1

⇒ t = R*C

if t= 300 s, and R = 10³ Ω, we can solve for C as follows:

C = \frac{t}{R} = \frac{3e2 s}{1e3 ohms} = 0.3 F

So, the required value for C is 0.3 F.

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This is the C++ code for the above problem:

#include<bits/stdc++.h>

using namespace std;

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int funLevel = 0;

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int max = 0, index = 0, sum = 0 ;

for(int i=1; i<11; i++){ //this loop is to run through whole plan arry

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//in this case loop should run to 366,but for example it is 11

//as my size of plan array is 11

for(int j=0; j<duration; j++) { // this loop is for that index to index+duration to calc

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sum = sum + prefs[plan[i]];

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return index;

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int main() {

int ngames = 5;

int prefs[] = { 1,2,0,5,2 };

int plan[] = { 0,2,0,3,3,4,0,1,2,3,3 };

int start = 1;

int duration = 4;

cout << computeFunLevel(start, duration, prefs, ngames, plan) << endl;

cout << computeFunLevel(start, 555, prefs, ngames, plan) << endl;

cout << findBestVacation(4, prefs, ngames, plan) << endl;

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The screen of the program is given below.

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