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notsponge [240]
3 years ago
5

Early American rockets used an RC circuit to set the time for the rocket to begin re-entry after launch (true story). Assume the

capacitor is initially charged, and then discharge begins at launch, t = 0 (this was when the umbilical connector was disconnected). Further assume the resistor in the RC circuit is 1k Ω, and the control circuit begins re-entry when the voltage drops ~63% or to ~37% of full-scale (i.e. 1 time constant), and re-entry is desired to commence at 5 minutes (i.e. 300 seconds after launch). Calculate the capacitor value required.
Engineering
1 answer:
koban [17]3 years ago
3 0

Answer:

C = 0.3 F

Explanation:

The expression for a voltage in a capacitor with an initial voltage V₀, as a function of time, is given by the following equation:

V= Vo*e^{-t/RC}

When V = =.37*V₀, we have the following expression:

\frac{V}{Vo} = e^{-t/RC} = 0.37

Applying ln to both sides, we have:

\frac{-t}{RC} = ln 0.37 = -1

⇒ t = R*C

if t= 300 s, and R = 10³ Ω, we can solve for C as follows:

C = \frac{t}{R} = \frac{3e2 s}{1e3 ohms} = 0.3 F

So, the required value for C is 0.3 F.

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Lilit [14]

Answer:

w = 10.437 kips

deflection at 1/4 span  20.83\E ft

at mid span = 1.23\E ft

shear stress  7.3629 psi

Explanation:

area of cross section = 18*76

length of span = 32 ft

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we know that

moment = load *eccentricity

334 = w * 32

w = 10.437 kips

deflection at 1/4 span

\delta = \frac{wa^2b^2}{3EI}

= \frac{10.4375*8^2 *24^2}{3E \frac{BD^3}{12}}

         =\frac{10.437 *8^2*24^2}{3E \frac{18*16^3}{12}}

         = 20.83\E ft

at mid span

\delta = \frac{wl^3}{48EI}

= \frac{10.43 *32^3}{48 *E*\frac{18*16^3}{12}}

\delta = 1.23\E ft

shear stress

\tau = \frac{w}{A} = \frac{10.43 7*10^3}{18*76} =7.3629 psi

6 0
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Fill in the empty function so that it returns the sum of all the divisors of a number, without including it. A divisor is a numb
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Answer:

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#include<iostream>

using namespace std;

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int result = 0;

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for (int i=2; i<=(num/2); i++)

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cout<<result+1;

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dimulka [17.4K]

Answer:

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Explanation:

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