1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Andrew [12]
4 years ago
8

Air at 20 C and 1 atm flows over a flat plate at 35 m/s. The plate is 75 cm long and is maintained at 60 с. Assuming unit depth

in the x direction, calculate the heat transfer from the plate.
Engineering
1 answer:
Alja [10]4 years ago
8 0

Answer:

Q=3198.744 W/m

Explanation:

Given that

Air temperature=20 C

Velocity V= 35 m/s

Temperature of surface= 60 C

Length of plate= 75 cm

Now first find the properties of air at mean temperature of 20 and 60,it means that  properties of air at  temperature 40 C

\rho=1.12 \frac{Kg}{m^3}

\nu =1.69\times 10^{-5}\frac{m^2}{s}

K=0.027\frac{W}{m-K}

Pr=0.71

Lets find the Reynolds number

Re=\dfrac{vL}{\nu }

Re=\dfrac{35\times0.75}{1.69\times 10^{-5}}

Re=15.53\times10^5

So this is turbulent flow

Nusselt equation of turbulent flow

Nu=0.037Re^{\frac{4}{5}}Pr^{\frac{1}{3}}

Now by putting the values

Nu=0.037\times (15.53\times10^5)^{\frac{4}{5}}\times 0.71^{\frac{1}{3}}

Nu=2961.68

We know that

NU=\dfrac{hL}{K_{air}}

So

2961.68=\dfrac{h\times 0.75}{0.027}

h=106.68\frac{W}{m^2-K}

So heat transfer

Q=hAΔT

Q=106.68 x 0.75 x 1 x (60-20)

Q=3198.744 W/m

You might be interested in
What is the fastest motorcycle in the world ?
givi [52]

Answer:

Kawasaki Ninja H2R – top speed: 222 mph. This one is another beast in the form of a bike. ...

MTT Turbine Superbike Y2K – top speed: 227 mph. This bike is one of the most powerful production motorcycles. ...

Suzuki Hayabusa – top speed: 248 mph. 1340cc

8 0
3 years ago
Read 2 more answers
In your opinion...
ch4aika [34]

Answer:no

TTHANLS FOR FREE POINTS

Explanation:

8 0
3 years ago
True or false It is legal to pass in Florida when approaching within 100 feet of or traversing any railroad crossing grade croea
Iteru [2.4K]
That is a false statement.
3 0
3 years ago
Select the best answer for the question.
dalvyx [7]
I think the Acid level
5 0
3 years ago
Water vapor at 10bar, 360°C enters a turbine operatingat steady state with a volumetric flow rate of 0.8m3/s and expandsadiabati
Artyom0805 [142]

Answer:

A) W' = 178.568 KW

B) ΔS = 2.6367 KW/k

C) η = 0.3

Explanation:

We are given;

Temperature at state 1;T1 = 360 °C

Temperature at state 2;T2 = 160 °C

Pressure at state 1;P1 = 10 bar

Pressure at State 2;P2 = 1 bar

Volumetric flow rate;V' = 0.8 m³/s

A) From table A-6 attached and by interpolation at temperature of 360°C and Pressure of 10 bar, we have;

Specific volume;v1 = 0.287322 m³/kg

Mass flow rate of water vapour at turbine is defined by the formula;

m' = V'/v1

So; m' = 0.8/0.287322

m' = 2.784 kg/s

Now, From table A-6 attached and by interpolation at state 1 with temperature of 360°C and Pressure of 10 bar, we have;

Specific enthalpy;h1 = 3179.46 KJ/kg

Now, From table A-6 attached and by interpolation at state 2 with temperature of 160°C and Pressure of 1 bar, we have;

Specific enthalpy;h2 = 3115.32 KJ/kg

Now, since stray heat transfer is neglected at turbine, we have;

-W' = m'[(h2 - h1) + ((V2)² - (V1)²)/2 + g(z2 - z1)]

Potential and kinetic energy can be neglected and so we have;

-W' = m'(h2 - h1)

Plugging in relevant values, the work of the turbine is;

W' = -2.784(3115.32 - 3179.46)

W' = 178.568 KW

B) Still From table A-6 attached and by interpolation at state 1 with temperature of 360°C and Pressure of 10 bar, we have;

Specific entropy: s1 = 7.3357 KJ/Kg.k

Still from table A-6 attached and by interpolation at state 2 with temperature of 160°C and Pressure of 1 bar, we have;

Specific entropy; s2 = 8.2828 KJ/kg.k

The amount of entropy produced is defined by;

ΔS = m'(s2 - s1)

ΔS = 2.784(8.2828 - 7.3357)

ΔS = 2.6367 KW/k

C) Still from table A-6 attached and by interpolation at state 2 with s2 = s2s = 8.2828 KJ/kg.k and Pressure of 1 bar, we have;

h2s = 2966.14 KJ/Kg

Energy equation for turbine at ideal process is defined as;

Q' - W' = m'[(h2 - h1) + ((V2)² - (V1)²)/2 + g(z2 - z1)]

Again, Potential and kinetic energy can be neglected and so we have;

-W' = m'(h2s - h1)

W' = -2.784(2966.14 - 3179.46)

W' = 593.88 KW

the isentropic turbine efficiency is defined as;

η = W_actual/W_ideal

η = 178.568/593.88 = 0.3

8 0
3 years ago
Other questions:
  • A power company desires to use groundwater from a hot spring to power a heat engine. If the groundwater is at 95 deg C and the a
    7·1 answer
  • The pistons of a V-6 automobile engine develop 226.5 hp. If the engine driveshaft rotational speed is 4700 RPM and the torque is
    14·1 answer
  • Plz help me
    12·1 answer
  • For a brass alloy, the following engineering stresses produce the corresponding plastic engineering strains prior to necking:
    9·1 answer
  • Please help I need it by today!!!
    10·1 answer
  • Question 3 (5 points)
    7·1 answer
  • Ma puteti ajuta cu un argument de 2 pagini despre inlocuirea garniturii de etansare de pe pistonul etrierului de franare la un a
    10·1 answer
  • Give three examples of how engineering has made human life better in your opinion.
    13·1 answer
  • What is the function rule for the line? f(x)=−32x−2f(x)=−23x−2f(x)=32x−2f(x)=−32x+2A coordinate grid with x and y axis ranging f
    6·1 answer
  • 10.16.1: LAB: Interstate highway numbers (Python)
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!