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SashulF [63]
3 years ago
6

Studying the decay of radioactive isotopes in dead organisms helps scientists to identify fossilized remains. The ratio of C-12

to C-14 in the atmosphere is 1 x 1012. The table shows this ratio inside the body of three organisms.
C12/C14 Ratio
Organism C12/C14 Ratio
X 8 x 1012
Y 2 x 1012
Z 1 x 1012


What can most likely be concluded from the above information?
Only Organism Z is alive, and Organism X has been dead longer than Organism Y.
Only Organism Z is alive, and Organism Y has been dead longer than Organism X.
Only Organism X is alive, and Organism Y has been dead longer than Organism Z.
Only Organism X is alive, and Organism Z has been dead longer than Organism Y.
Chemistry
1 answer:
satela [25.4K]3 years ago
7 0

Answer:

Only Organism Z is alive, and Organism X has been dead longer than Organism Y.

Explanation:

After the death of an organism, there is radioactive disintegration of C-14 allotrope of carbon, which increases the ratio of C-12 to C-14 in a dead organism as compared to a living organism.

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The electron configuration of an element is shown below.
g100num [7]

Answer:

helium family or neon family

Explanation:

you can use p

5 0
3 years ago
The chemical equation for a reaction between K2Cr2O7 and HCl is shown. K2Cr2O7 + 14HCl → 2CrCl3 + 2KCl + 3Cl2 + 7H2O
guapka [62]

<u>Answer: </u>The correct answer is Option b.

<u>Explanation:</u>

Oxidizing agent is defined as the chemical reagent which helps the other chemical compound to get oxidized and itself gets reduced. The oxidation state for these species gets reduced because they are undergoing reduction reaction.

For the given chemical equation:

K_2Cr_2O_7+14HCl\rightarrow 2CrCl_3+2KCl+3Cl_2+7H_2O

Oxidation state of Chromium is getting reduced from +6 to +3 and oxidation state of chlorine getting increased from -1 to 0.

Hence, K_2Cr_2O_7 acts like and oxidizing agent because it is itself getting reduced to CrCl_3

Therefore, the correct answer is Option b.

4 0
3 years ago
A sample of aluminum is placed in a 25-ml graduated cylinder containing 10.0 ml of water. the level of the water rises to 18.0 m
OLga [1]
To determine the mass of the sample, first find the volume difference after and before the aluminum was placed, the volume change is equal to the volume of the submerged object, in this case aluminum.

Then knowing volume of aluminum and the density of it, we can solve for the mass.

D = m/v

Dv = m

2.7 g/ml • 8 ml = 21.6 grams.
5 0
3 years ago
Read 2 more answers
How many moles are found in 133 g of Mg3 N2
konstantin123 [22]
Magnesium nitride weighs 100.95 g/mol

133/100.95 = 1.32 mols
7 0
3 years ago
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0.415 g of an unknown triprotic acid are used to make a 100.00 mL solution. Then 25.00 mL of this solution is transferred to an
Arturiano [62]

Answer:

Explanation:

Initial burette reading = 1.81 mL

final burette reading = 39.7 mL

volume of NaOH used = 39.7 - 1.81 = 37.89 mL .  

37.89 mL of .1029 M NaOH is used to neutralise triprotic acid

No of moles contained by 37.89 mL of .1029 M NaOH

= .03789 x .1029 moles

= 3.89 x 10⁻³ moles

Since acid is triprotic ,  its equivalent weight = molecular weight / 3

No of moles of triprotic acid = 3.89 x 10⁻³ / 3

= 1.30   x 10⁻³ moles .

8 0
3 years ago
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