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SashulF [63]
3 years ago
6

Studying the decay of radioactive isotopes in dead organisms helps scientists to identify fossilized remains. The ratio of C-12

to C-14 in the atmosphere is 1 x 1012. The table shows this ratio inside the body of three organisms.
C12/C14 Ratio
Organism C12/C14 Ratio
X 8 x 1012
Y 2 x 1012
Z 1 x 1012


What can most likely be concluded from the above information?
Only Organism Z is alive, and Organism X has been dead longer than Organism Y.
Only Organism Z is alive, and Organism Y has been dead longer than Organism X.
Only Organism X is alive, and Organism Y has been dead longer than Organism Z.
Only Organism X is alive, and Organism Z has been dead longer than Organism Y.
Chemistry
1 answer:
satela [25.4K]3 years ago
7 0

Answer:

Only Organism Z is alive, and Organism X has been dead longer than Organism Y.

Explanation:

After the death of an organism, there is radioactive disintegration of C-14 allotrope of carbon, which increases the ratio of C-12 to C-14 in a dead organism as compared to a living organism.

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The correct answer would be metamorphosis.

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The life cycle of a butterfly can be summarized as shown below.

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What is the volume of 4.00 moles of CO2 gas at STP?
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Answer:

89.6L

Explanation:

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What is the hybridization of the central atom in becl2?
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In each case, calculate the appropriate ratio to show that the information given is consistent with the law of multiple proporti
Alchen [17]

Answer:

(a) 3:2; (b) 2:1

Explanation:

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That is, if one compound has a ratio r₁ and the other has a ratio r₂, the ratio of the ratios r is in small whole numbers.

(a) Ammonia and hydrazine.

In ammonia, the mass ratio of H:N is r₁ = 0.2158/1

In hydrazine, the mass ratio of H:N is r₂ = 0.1439/1

The ratio of the ratios is:

r = \dfrac{r_{1}}{r_{2}} = \dfrac{ 0.2158}{0.1439} = \dfrac{1.500 }{1} = \dfrac{2.999}{2} \approx \mathbf{\dfrac{3}{2}}\\\\\text{The relative amounts of H in the two compounds are in the ratio }\boxed{\mathbf{\dfrac{3}{2}}}

(b) Nitrogen oxides

In nitrogen monoxide, the mass ratio of O:N is r₁ = 1.142/1

In dinitrogen monoxide, the mass ratio of O:N is r₂ = 0.571/1

The ratio of the ratios is:

r = \dfrac{r_{1}}{r_{2}} = \dfrac{ 1.142}{0.571} = \dfrac{2.000 }{1} \approx \mathbf{\dfrac{2}{1}}\\\\\text{The relative amounts of O in the two compounds are in the ratio }\boxed{\mathbf{\dfrac{2}{1}}}

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3 years ago
Which of the following is a direct result of hydrogen bonding?
prisoha [69]
Cohesion and adhesion
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