The chemical formula for cesium oxide is Cs2O. What is the charge of cesium?
2 answers:
Answer : The charge of cesium is, (+1)
Explanation :
Oxidation state or number : Oxidation state represent the number of electrons gained or lost by the atoms of an element in the compound. That means it also tells us about the charge present on the cation and the anion.
Oxidation state or number are generally written with the sign (+) and (-) first and then the magnitude.
When the atoms are present in their elemental state then the oxidation number will be zero.
Oxidation number of oxygen (O) in compounds is usually equal to (-2).
The given chemical formula of cesium oxide is,
Let the oxidation state of 'Cs' be, 'x'
Therefore, the charge of cesium is, (+1)
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Answer:
The partial pressure of argon in the flask = 71.326 K pa
Explanation:
Volume off the flask = 0.001
Mass of the gas = 1.15 gm = 0.00115 kg
Temperature = 25 ° c = 298 K
Gas constant for Argon R = 208.13
From ideal gas equation P V = m RT
⇒ P =
Put all the values in above formula we get
⇒ P = × 208.13 × 298
⇒ P = 71.326 K pa
Therefore, the partial pressure of argon in the flask = 71.326 K pa
Avagadro's law gives the relationship between volume of gas and amount of moles of gas. It states that at constant temperature and pressure, volume of gas (V) is directly proportional to number of moles of gas (n).
V/n = k
where k - constant
V1 = 42.0 L
n1 = 1.90 mol
n2 = 1.90 mol - 0.600 = 1.30 mol
substituting the values in the equation
V = 28.7 L
Volume of the gas is 28.7 L
V/n = k
where k - constant
V1 = 42.0 L
n1 = 1.90 mol
n2 = 1.90 mol - 0.600 = 1.30 mol
substituting the values in the equation
V = 28.7 L
Volume of the gas is 28.7 L