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kodGreya [7K]
4 years ago
6

The chemical formula for cesium oxide is Cs2O. What is the charge of cesium?

Chemistry
2 answers:
Cerrena [4.2K]4 years ago
8 0

your answer is A  if i am wrong let me know

svetlana [45]4 years ago
4 0

Answer : The charge of cesium is, (+1)

Explanation :

Oxidation state or number : Oxidation state represent the number of electrons gained or lost by the atoms of an element in the compound.  That means it also tells us about the charge present on the cation and the anion.

Oxidation state or number are generally written with the sign (+) and (-) first and then the magnitude.

When the atoms are present in their elemental state then the oxidation number will be zero.

Oxidation number of  oxygen (O)  in compounds is usually equal to (-2).

The given chemical formula of cesium oxide is, Cs_2O

Let the oxidation state of 'Cs' be, 'x'

2x+1(-2)=0\\\\2x-2=0\\\\x=\frac{2}{2}\\\\x=+1

Therefore, the charge of cesium is, (+1)

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1. Determine whether or not the equation below is balanced. If it isn’t balanced, write the balanced form. Also, identify the re
strojnjashka [21]

Answer:

- Not balanced.

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- Products: ZnCl₂ and  H₂.

- Substitution reaction.

Explanation:

Hello,

In this case, for the given reaction:

Zn  +  HCI  →  ZnCl₂ +  H₂

We can see that it is not balanced due to the fact that at the left side we have one hydrogen atom whereas at the right side two, taking into account the number must be same as well as chlorine. Thus, in order to balance we write:

Zn  +  2HCI  →  ZnCl₂ +  H₂

And that is enough. Moreover, we can see that the chemical species at the left side of the equation are the reactants and those at the right side the products, thus we have:

Reactants: Zn  and HCI .

Products: ZnCl₂ and  H₂.

Finally, since we can see that the chlorine is at the reactants with hydrogen, but at the end with the zinc, and the initial zinc is alone as well as the yielded hydrogen we can infer this is a substitution reaction.

Best regards.

5 0
4 years ago
how many grams of alcl3 are produced when 355 ml of 1.65 m hcl solution are reacted with excess al according to the reaction?
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According to the reaction, when 355 ml of 1.65 m Hydrochloric acid solution are combined with too much aluminum, 26.03 g of aluminum chloride is created.

An inorganic substance with the formula AlCl3 is aluminum chloride, also referred to as aluminum trichloride. It takes the form of [Al(H2O)6] hexahydrate. Aluminum chloride is ALCl3, which is composed of six water molecules. Aqueous hydrochloric acid, also referred to as muriatic acid, is a type of hydrochloric acid. It is a colourless solution with an overpowering odor. Strong acid is how it is categorized.

2 Al(s) + 6 HCl is the given reaction. ———-> 2 AlCl3 + 3H2

Using the provided data

The amount of HCl in moles is n= Volume * Concentration = 0.58575 mol (1.65 M * 355 ml)/1000 ml

based on the response,

It takes 6 mols of HCl. To neutralize 2 moles of aluminum, 0.58575 mol of hydrochloric acid must be used.

using the cross-multiplication method, 0.19525 moles are obtained by multiplying 0.58575% by 2/ 6.

Weight of the AlCl3 = 0.1952 moles * 133.340538 g/mol = 26.03 g

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5 0
1 year ago
The element iodine would be expected to form covalent bond(s) in order to obey the octet rule. Use the octet rule to predict the
zhannawk [14.2K]

Answer:

HI (hydrogen iodide).

Explanation:

Hello,

In this case, since iodine is in group VIIA, it has seven valence electrons at its outer shell, which means that it only needs one bond to attain the octet. Moreover, since hydrogen has just one electron at its outer shell, one hydrogen turns out enough to obey the octet when hydrogen and iodine bond as shown below:

H-I

Therefore, the required formula is:

HI

Which is hydrogen iodide.

Best regards.

7 0
3 years ago
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