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kodGreya [7K]
4 years ago
6

The chemical formula for cesium oxide is Cs2O. What is the charge of cesium?

Chemistry
2 answers:
Cerrena [4.2K]4 years ago
8 0

your answer is A  if i am wrong let me know

svetlana [45]4 years ago
4 0

Answer : The charge of cesium is, (+1)

Explanation :

Oxidation state or number : Oxidation state represent the number of electrons gained or lost by the atoms of an element in the compound.  That means it also tells us about the charge present on the cation and the anion.

Oxidation state or number are generally written with the sign (+) and (-) first and then the magnitude.

When the atoms are present in their elemental state then the oxidation number will be zero.

Oxidation number of  oxygen (O)  in compounds is usually equal to (-2).

The given chemical formula of cesium oxide is, Cs_2O

Let the oxidation state of 'Cs' be, 'x'

2x+1(-2)=0\\\\2x-2=0\\\\x=\frac{2}{2}\\\\x=+1

Therefore, the charge of cesium is, (+1)

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The plant on the left is growing more because it has been receiving more water
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Answer:

am not sure i understand but i think it got more chlorophyll

6 0
3 years ago
determine the final temperature of a gold nugget parentheses Mass equals 376 G parentheses that starts at 398k and loses 4.85 KJ
maw [93]

Answer:

297.23 K

Explanation:

Given that:

the mass of the gold nugget (m) = 376 g

the initial temperature T_1 = 398 K

amount of heat lost Q = -4.85 kJ = -4.85 × 10³

specific heat capacity (c) = 0.128 J/g° C

Using the formula for calculating the Heat energy

Q = mc\Delta T \\  \\  Q = m\times c\times (T_2-T_1)

-4.85 \times 10^3 = 376 \times  0.128 \times (T_2 - 398) \\ \\ -4.85\times 10^3 =  48.128(T_2 - 398) \\ \\ \dfrac{-4.85\times 10^3}{48.128}= (T_2 - 398) \\ \\-100.77 = T_2 -398\\\\T_2 = -398 +100.77\\ \\ \mathbf{ T_2 = 297.23K}

7 0
3 years ago
Rank the following steps involved in preparing a dilute solution from a stock solution in order from first to last.
Serggg [28]

Answer: C - B - A - D

Explanation:

-Obtain a flask that is thoroughly cleaned

-Add the desired amount of stock solution

-Add deionized water until the volume reaches the mark on the flask.

- Cap the flask and invert several times to thoroughly mix the solution.

5 0
3 years ago
Hurry PLEASE HELP!
avanturin [10]

B. 11,540

<h3>Further explanation </h3>

The atomic nucleus can experience decay into 2 particles or more due to the instability of its atomic nucleus.  

Usually radioactive elements have an unstable atomic nucleus.  

General formulas used in decay:  

\large{\boxed{\bold{N_t=N_0(\dfrac{1}{2})^{t/t\frac{1}{2} }}}

T = duration of decay  

t 1/2 = half-life  

N₀ = the number of initial radioactive atoms  

Nt = the number of radioactive atoms left after decaying during T time  

Nt=25 g

No=100 g

t1/2=5770 years

\tt 25=100\dfrac{1}{2}^{T/5770}\\\\\dfrac{1}{4}=\dfrac{1}{2}^{T/5770}\\\\2=T/5770\rightarrowT=11540~years

7 0
3 years ago
Write balanced equations for all the reactions in the catabolism of glucose to two molecules of glyceraldehyde 3-phosphate (the
Reil [10]

Solution :

The balanced chemical equation are

The Catabolism of the glucose takes place in five stages :

1. Glucose + $ATP$ → glucose - $6$ - phosphate $+ ADP$  ,  $\Delta G^0=-16.7 \ kJ/mol$

2. Glucose - $6$ - phosphate → Fructose - $6$ - phosphate ,  $\Delta G^0=1.7 \ kJ/mol$

3. Glucose - $6$ - phosphate + $ATP$ → $ADP$ + Fructose - $1,6- \text{biophosphate}$,  $\Delta G^0=-14.2 \ kJ/mol$

4. Fructose - $1,6- \text{biophosphate}$  → dihydroxyacetonephosphate + glyceraldehyde  $-3 - $ phosphate,   $\Delta G^0=23.8 \ kJ/mol$

5. Dihydroxyacetonephosphate → glyceraldehyde  $-3 - $ phosphate , $\Delta G^0=7.5 \ kJ/mol$

Therefore, the overall net equations

Glucose + $2ATP \rightarrow$ glyceraldehyde  $-3 - $ phosphate + $2ADP$ $\Delta G^0=2.1 \ kJ/mol$

5 0
3 years ago
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