Answer:
The answer is below
Explanation:
The question is not complete since the liquid density is not given.
Archimedes principle states that a body at rest in a fluid is acted upon by an upward force known as the buoyant force. The buoyant force is equal to the weight of the fluid displaced.
An object floats when it is placed in a liquid only if the density of the object is less than the density of the liquid. Therefore those metals with density less than that of mercury would float while those with density greater than mercury would sink.
I would say 648858. bc yes
The velocity is given by:
V = √(Vx²+Vy²)
V = velocity, Vx = horizontal velocity, Vy = vertical velocity
Given values:
Vx = 6m/s, Vy = 12m/s
Plug in and solve for V:
V = √(6²+12²)
V = 13.42m/s
Now find the direction:
θ = tan⁻¹(Vy/Vx)
θ = angle of velocity off horizontal, Vy = vertical velocity, Vx = horizontal velocity
Given values:
Vx = 6m/s, Vy = 12m/s
Plug in and solve for θ:
θ = tan⁻¹(12/6)
θ = 63.4°
The resultant velocity is 13.42m/s at an angle of 63.4° off the horizontal.
The change in momentum of an object equals the impulse applied to it
