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Nesterboy [21]
1 year ago
14

Compared to the wavelength of incident light, diffuse reflection occurs when the size of surface irregularities is?

Physics
1 answer:
bagirrra123 [75]1 year ago
5 0

Compared to the wavelength of the incident light, diffuse reflection occurs when the size of surface irregularities is comparable to the size of the wavelength of the light.

The distance between the two crests or troughs of the light wave is known as the wavelength of light. Using the Greek letter lambda 'λ', it is identified. As a result, wavelength refers to the separation between one wave's crest or dip and the following wave.

In contrast to specular reflection, diffuse reflection involves the reflection of light, other waves, or particles off a surface so that rays incident on the surface are scattered at a variety of angles.

Refer to more about wavelength here

brainly.com/question/13533093

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In a double-slit experiment, the third-order maximum for light of wavelength 510 nm is located 17 mm from the central bright spo
Marysya12 [62]

Answer:

14.9 mm

Explanation:

We know dsinθ = mλ where d = separating of slit, m = order of maximum = 3 and λ = wavelength = 510nm = 510 × 10⁻⁹ m

Also tanθ = L/D where L = distance of m order fringe from central bright spot = 17 mm = 0.017 m and D = distance of screen from slit = 1.6 m

So, sinθ = mλ/d

Since θ is small, sinθ ≅ tanθ

So,

mλ/d = L/D

d = mλD/L

Substituting the values of the variables into the equation, we have

d = 3 × 510 × 10⁻⁹ m × 1.6 m/0.017 m

d = 2448 × 10⁻⁹ m²/0.017 m

d = 144000 × 10⁻⁹ m

d = 1.44 × 10⁻⁴ m

d = 0.144 × 10⁻³ m

d = 0.144 mm

Now, for the second-order maximum, m' of the 670 nm wavelength of light,

m'λ'/d = L'/D where m' = order of maximum = 2, λ' = wavelength of light = 670 nm = 670 × 10⁻⁹ m, d = slit separation = 0.144 mm = 0.144 × 10⁻³ m, L' = distance of second order maximum from central bright spot and D = distance of screen from slit = 1.6m

So, L' = m'λ'D/d

So, substituting the values of the variables into the equation, we have

L' = 2 × 670 × 10⁻⁹ m × 1.6 m/0.144 × 10⁻³ m

L' = 2144  × 10⁻⁹ m²/0.144 × 10⁻³ m

L' = 14888.89 × 10⁻⁶ m

L' = 0.01488 m

L' ≅ 0.0149 m

L' = 14.9 mm

4 0
3 years ago
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