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Anna007 [38]
3 years ago
7

A car with a mass of 725 kg is moving at 32 m/s toward the east. What is the momentum of the car? A second car with a mass of 2,

175 kg has the same momentum. What is its velocity? Use details to support your answer.
Physics
1 answer:
Elden [556K]3 years ago
7 0

Answer:

A compact car, with mass 725 kg, ... at 115 km/h toward the east. ... b. A second car, with a mass of 2175 kg, has the same momentum. What is its ... Glisens : m = 2175 kg;. D 21,32 xrolka. anknown. r = ? 110.6 mis east

Explanation:

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a)You throw a stone horizontally at a speed of 5.0 m/s from the top of a cliff that is 78.4 m high.

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now, using the equation of motion

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The magnitude of vector λa is 5. Find the value of λ, if: a = (−6, 8)
Nata [24]

Given :

\:  \:

  • \color{pink}{\rm \: The \:magnitude \:of \:vector\: λa\: is \:  {\bold5\:}}

\:

  • \color{green}{\rm \: a = (−6, 8)}

\:

To Find :

\:  \:

  • \orange{ \rm\: value \:  of \:  \bold{ λ \: }}

\:  \:

\rm \: The \:  magnitude \:  of \:  the  \: vector  \: a  \: is  \:  ||a|| = \sqrt{(-6)^2+ 8^2)}  \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:    \:  \:  \rm = \sqrt{( 36+64)} \\ \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:\:  \: \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:\:\:   \: \:\:= \rm\sqrt{100} \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \: \:  \:  \:   \:  \:  \:  \: \:  \:  \:  \:  \:  \:  \:  \:  \:\\\:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \:  \:\: \rm   \underline{\boxed{\red{ \:  = 10 \: }}} \green✓

\:  \:

\rm \: Therefore, \:  λ =   \cancel{\frac{5}{10} } \\   \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \underline  {  \: \boxed{ \red{\: \rm = 0.5\:}}}{  \green ✓ }

Hope helps ~

\color{purple}\frak{SarcasticSmileeᥫ᭡}

`

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