From the Graham's law of effusion;
R1/R2 = √MM2/√MM1
Molar mass of chlorine gas is 71
Therefore;
1.87= √ 71 /√mm1
= 1.87² = 71/mm1
mm1 = 71/1.87²
= 71/3.4969
= 20.3
Thus, the molar mass of the other gas is 20.3 , and i think the gas is neon
Answer:
C₅ H₁₂ O
Explanation:
44 g of CO₂ contains 12 g of C
30.2 g of CO₂ will contain 12 x 30.2 / 44 = 8.236 g of C .
18 g of H₂O contains 2 g of hydrogen
14.8 g of H₂0 will contain 1.644 g of H .
total compound = 12.1 out of which 8.236 g is C and 1.644 g is H , rest will be O
gram of O = 2.22
moles of C, O, H in the given compound = 8.236 / 12 , 2.22 / 16 , 1.644 / 1
= .6863 , .13875 , 1.644
ratio of their moles = 4.946 : 1 : 11.84
rounding off to digits
ratio = 5 : 1 : 12
empirical formula = C₅ H₁₂ O
Answer:
V=0.3×22.4=6.72 liters hope this helps
Answer:
The answer to your question is: Includes sulfur and gain two electrons
Explanation:
Includes Chlorine This option is wrong, Chlorine belongs to group VII.
Includes Sulfur This option is true, Group VI includes Oxygen, Sulfur, Selenium, Tellurium.
Gain 2 electrons
. This option is true, Elements in group VI have six valence electrons so they gain to electrons to become estable.
Tend to form +2 ions This option is wrong, this elements form -2 ions
Have 5 valence electrons This option is wrong, this elements have 6 valence electrons.
Do you mean which one out of water and carbon tetrachloride
if so it will be water
