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3 years ago

Why it is difficult to accurately represent ammonia two-dimensionally?

1 answer:

8 0

According to the valence shell electron pair repulsion (VSPER) theory, an ammonia molecule <span> has a </span>trigonal pyramidal<span> shape with an experimental bond angle measure of 106.7 degrees. This is why it is difficult to accurately represent ammonia two-dimensionally because the molecular structure entails a 3-D projection with angles in it unlike the linear structure.</span>

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Which planet formed near the sub where the solar system l’s temperatures were very high

Harrizon [31]

Answer:

Mars

Explanation:

Terrestrial or inner planets like Mars and Venus were formed near the Sun where the solar system's temperatures were very high.

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3 years ago

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URGENT!!! What is the balanced form of this equation?

Ostrovityanka [42]

Explanation: This is a reaction of oxidation of $H_2O_2$ in the presence of acidified $KMnO_4$ . Acidified $KMnO_4$ is a strong oxidizing agent.

To balance out the $H^+$ on the reactant side, we write $H_2O$ on the product side.

Balancing out the following reaction gives us:

$2MnO_4^-+6H^++5H_2O_2\rightarrow 2Mn^{2+}+8H_2O+5O_2$

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3 years ago

A pound of margarine costs $1.39. What is the cost of a kilogram of margarine

den301095 [7]

Answer:

3.064 $

Solution:

First of all we will find the number of pounds contained by one Kg. Therefore, it is found that,

1 Kilogram = 2.20462 Pounds

Hence, as given,

1 Pound of Margarine costs = 1.39 Dollars

So,

2.20462 Pounds Margarine will cost = X Dollars

Solving for X,

X = (2.20462 Pounds × 1.39 Dollars) ÷ 1 Pound

X = 3.064 Dollars

8 0

3 years ago

A gas mixture with 4 mol of Ar, x moles of Ne, and y moles

maks197457 [2]

Answer:

a) $\Delta G_{mixing}=\frac{R*T}{12}*[4*ln (1/3) +x*ln (x/12) +(8-x)*ln ((8-x)/12)]$

b) $x=4$

c) $\Delta G_{max}=-2721.9 J/mol$

Explanation:

Gas mixture:

$n_{Ar}= 4 mol$

$n_{Ne}= x mol$

$n_{Xe}= y mol$

$n_{tot}= n_{Ar} + n_{Ne} + n_{Xe}=3*n_{Ar}$

$n_{Ne} + n_{Xe}=2*n_{Ar}$

$x + y=8 mol$

$y=8 mol- x$

Mol fractions:

$x_{Ar}=\frac{4 mol}{12 mol}=1/3$

$x_{Ne}=\frac{x mol}{12 mol}=x/12$

$x_{Xe}=\frac{8 - x mol}{12 mol}=(8-x)/12$

Expression of $\Delta G_{mixing}$

$\Delta G_{mixing}=R*T*\sum_{i]*x_i*ln (x_i)$

$\Delta G_{mixing}=R*T*[1/3*ln (1/3) +x/12*ln (x/12) +(8-x)/12*ln ((8-x)/12)]$

$\Delta G_{mixing}=\frac{R*T}{12}*[4*ln (1/3) +x*ln (x/12) +(8-x)*ln ((8-x)/12)]$

Expression of $\Delta G_{max}$

$\frac{d \Delta G_{mixing}}{dx}=0$

$\frac{d \Delta G_{mixing}}{dx}=\frac{R*T}{12}*[ln (x/12)+12-ln ((8-x)/12)-12]$

$0=\frac{R*T}{12}*[ln (x/12)-ln ((8-x)/12)$

$0=[ln (x/12)-ln ((8-x)/12)$

$ln (x/12)=ln ((8-x)/12)$

$x=(8-x)$

$x=4$

$\Delta G_{max}=\frac{8.314*298}{12}*[4*ln (1/3) +4*ln (4/12) +(8-4)*ln ((8-4)/12)]$

$\Delta G_{max}=\frac{8.314*298}{12}*[4*ln (1/3) +4*ln (1/3) +(4)*ln (1/3)]$

$\Delta G_{max}=\frac{8.314*298}{12}*[12*ln (1/3)]$

$\Delta G_{max}=-2721.9 J/mol$

4 0

3 years ago

Which of the following groups have seven valence electrons and are very reactive?

valina [46]

Answer:

Column 17 halogens

Explanation:

To answer the question we need to know the following;

What are valence electrons?

Valence electrons are outermost electrons in the outermost energy level of an atom of any element.

What are halogens?

Halogens are group 7 elements that have seven valence electrons. They include, chlorine, fluorine, iodine, etc

What is the reactivity of halogens?

Halogens are the most reactive non-metals in the periodic table. They react by gaining one electron to attain a stable configuration.

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3 years ago

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