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Jlenok [28]
3 years ago
15

ANSWERS NEEDED ASAP

Chemistry
1 answer:
Artemon [7]3 years ago
3 0

1 and 2 the forces holding water molecules together are stronger than the forces holding alcohols molecules together these forces are stronger in water due to hydrogen bonding the intermolecular forces forces that hold the water together are stronger than alchol because water has hydrogen bonding hydrogen bonding is hydrogen being attracted to oxygen or flourine or chloroine the electronegativity differences are larger the forces holding the bonds are stronger its like hydrogen is holding on to oxygen strongly different types of forces are lomdon dispersion forces like helium which have low boiling point they have nothing holding them together water has hydrogen bonds alcohol doesnt have the hydrogen bonds water has and geometry vsper model polar and hydrogen bonds as water so theyre weaker.

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There are two isotopes of chlorine. below is a list of each and their mass and abundance. calculate the atomic mass of chlorine.
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Chlorine is very lequid structure
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Which describes any compound that has at least one element from group 17?
Contact [7]
The answer is HALIDE.
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A 50.0 mL sample of a 1.00 M solution of CuSO4 is mixed with 50.0 mL of 2.00 M KOH in a calorimeter. The temperature of both sol
Reika [66]

Answer : The enthalpy change for the process is 52.5 kJ/mole.

Explanation :

Heat released by the reaction = Heat absorbed by the calorimeter + Heat absorbed by the solution

q=[q_1+q_2]

q=[c_1\times \Delta T+m_2\times c_2\times \Delta T]

where,

q = heat released by the reaction

q_1 = heat absorbed by the calorimeter

q_2 = heat absorbed by the solution

c_1 = specific heat of calorimeter = 12.1J/^oC

c_2 = specific heat of water = 4.18J/g^oC

m_2 = mass of water or solution = Density\times Volume=1/mL\times 100.0mL=100.0g

\Delta T = change in temperature = T_2-T_1=(26.3-20.2)^oC=6.1^oC

Now put all the given values in the above formula, we get:

q=[(12.1J/^oC\times 6.1^oC)+(100.0g\times 4.18J/g^oC\times 6.1^oC)]

q=2623.61J

Now we have to calculate the enthalpy change for the process.

\Delta H=\frac{q}{n}

where,

\Delta H = enthalpy change = ?

q = heat released = 2626.61 J

n = number of moles of copper sulfate used = Concentration\times Volume=1M\times 0.050L=0.050mole

\Delta H=\frac{2623.61J}{0.050mole}=52472.2J/mole=52.5kJ/mole

Therefore, the enthalpy change for the process is 52.5 kJ/mole.

8 0
3 years ago
A hypothetical element consists of two isotopes of masses 86.95amu and 88.95amu with abundances of 35.5% and 64.5% respectively.
Art [367]

Answer: The average atomic mass of the element = 88.242amu

Explanation:

The abundance of the first isotope is =35.5%

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The average atomic mass of the first isotope =86.95amu X 35.5%  =86.95amu X 0.355 =30.8725 amu

The abundance of the second isotope =64.5%

Atomic mass of the second isotope =88.95amu

The average atomic mass of second isotope =88.95amu x 64.5% = 88.95amu x 0.645= 57.37275 amu

Now the average atomic mass =30.8725 +57.37275 = 88.242amu

OR using the formulae

Average atomic mass = [mass of isotope× its abundance] + [mass of isotope× its abundance] +...[ ] / 100

{(86.95amu X 35.5 )+(88.95amu x 64.5)}/100

8,824/100

=88.24amu

5 0
3 years ago
How is a mole defined?​
sattari [20]

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6 0
3 years ago
Read 2 more answers
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