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Sloan [31]
3 years ago
8

What is the acceleration of a 10.5 kg mass pushed by a 50.5 n force

Physics
1 answer:
Lina20 [59]3 years ago
8 0

Answer:4.8 m/s^2

Explanation:

mass=10.5kg

Force=50.5N

Acceleration =force ➗ mass

Acceleration =50.5 ➗ 10.5

Acceleration =4.8 m/s^2

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Name 2 things that have gears in them
Anvisha [2.4K]

BICYCLE

MOTOR BIKES

CARS

THEY ARE THE VEHICLES WHICH HAS GEARS IN THEM.

6 0
3 years ago
Which is an example of a vector quantity
swat32

Answer:

The answer to your question is C

Explanation:

acceleration is a vector quantity because it has both magnitude and direction

4 0
3 years ago
One end of a string is fixed. An object attached to the other end moves on a horizontal plane with uniform circular motion of ra
sveticcg [70]

Answer:

If both the radius and frequency are doubled, then the tension is increased 8 times.

Explanation:

The radial acceleration (a_{r}), measured in meters per square second, experimented by the moving end of the string is determined by the following kinematic formula:

a_{r} = 4\pi^{2}\cdot f^{2}\cdot R (1)

Where:

f - Frequency, measured in hertz.

R - Radius of rotation, measured in meters.

From Second Newton's Law, the centripetal acceleration is due to the existence of tension (T), measured in newtons, through the string, then we derive the following model:

\Sigma F = T = m\cdot a_{r} (2)

Where m is the mass of the object, measured in kilograms.

By applying (1) in (2), we have the following formula:

T = 4\pi^{2}\cdot m\cdot f^{2}\cdot R (3)

From where we conclude that tension is directly proportional to the radius and the square of frequency. Then, if radius and frequency are doubled, then the ratio between tensions is:

\frac{T_{2}}{T_{1}} = \left(\frac{f_{2}}{f_{1}} \right)^{2}\cdot \left(\frac{R_{2}}{R_{1}} \right) (4)

\frac{T_{2}}{T_{1}} = 4\cdot 2

\frac{T_{2}}{T_{1}} = 8

If both the radius and frequency are doubled, then the tension is increased 8 times.

5 0
2 years ago
1123123213213242141241
schepotkina [342]

Answer:

thanks for the points

Explanation:

8 0
3 years ago
Conservation of Momentum<br> No one likes you little trolls please send an actual answer
Olin [163]

Hello!

This is an example of an inelastic collision, where the two objects "stick" to each other after their collision. (The Goalkeeper CATCHES the puck).

We can write out the conservation of momentum formula:

m1vi + m2vi = m1vf + m2vf

Let:

m1 = mass of puck

m2 = mass of the goalkeeper

We know that the initial velocity of the goalkeeper is 0, so:

m1vi + m2(0) = m1vf + m2vf

m1vi = m1vf + m2vf

The final velocities will be the same, so:

m1vi = (m1 + m2)vf

Plug in the given values:

(0.16)(40)/ (0.16 + 120) = vf ≈ 0.0533 m/s

Using the equation for momentum:

p = mv

The object with the LARGER mass will have the greater momentum. Thus, the Goalkeeper has the largest momentum as p = mv; a greater mass correlates to a greater momentum since the velocity is the same between the two objects. The puck would have a momentum of p = (.16)(0.0533) = 0.008528 kgm/s, whereas the goalkeeper would have a momentum of

p =  (120)(0.0533) = 6.396 kgm/s.

3 0
2 years ago
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