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Zinaida [17]
4 years ago
14

If the bat emits a sound at a frequency of 80.2 kHzkHz and hears it reflected at a frequency of 83.5 kHzkHz while traveling at a

speed of 3.9 m/sm/s , calculate the speed of the insect.
Physics
1 answer:
solong [7]4 years ago
8 0

To solve this problem we will apply the concepts related to the Doppler Effect. The Doppler effect is the change in the perceived frequency of any wave movement when the emitter, or focus of waves, and the receiver, or observer, move relative to each other.

Mathematically it can be described as

v' = v (\frac{f' ( v - v_{bat}) - f ( v + v_{bat})}{f'(v-v_{bat}) + f ( v + v_{bat})})

Where,

v = Speed of sound

f' = Reflected frequency

f = Emitted Frequency

v_{bat} = Speed of the object

Assuming that the speed of the medium is the speed of sound of 343m / s, we will then have that:

v' = 343 (\frac{(83.5) (343 -3.9) - 80.2(343+3.9)}{83.5(343-3.9) + 80.2(343+4.3)})

v' = 3.0134m/s

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A criminalist collects small strands of fabric from a crime scene. Which type of evidence is he detecting?
kozerog [31]
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4 0
3 years ago
light waves with a frequency of 7.26 x 10^14 HZ lies in the violet region of the visible spectrum. what is the wavelength of thi
pogonyaev

Answer:

4.13×10⁻⁷ m

Explanation:

Applying

v = λf................... Equation 1

Wherfe v = speed of light, λ = wavelength of light, f = frequency of light.

make λ the subject of the equation

λ = v/f....................... Equation 2

Note: Light is an electromagnetic wave, and all electromagnetic wave moves with thesame speed which is 3×10⁸ m/s.

From the question,

Given: f = 7.26×10¹⁴ Hz

Constant: v = 3×10⁸ m/s

Substitute these values into equation 2

λ = (3×10⁸)/(7.26×10¹⁴)

λ = 4.13×10⁻⁷ m

7 0
3 years ago
A rock with a mass of 16 kilograms is put aboard an airplane in New York City and flown to Boston. How much work does the gravit
Law Incorporation [45]

The work done by the gravitational field of the earth on the rock is 9.998 x 10⁸ J.

<u>The given parameter include:</u>

the mass of the object, m₁ = 16 kg

Note: the mass of the earth, m₂ = 5.972 x 10²⁴ kg

  • The work done by the gravitational field of the earth is given as;

Work done = gravitational force (F) x radius of the earth (R)

Work \ done = \frac{Gm_1m_2}{R^2} \times R\\\\Work \ done = \frac{Gm_1m_2}{R} \\\\where;\\\\R \ is \ the \ radius \ of \ the \ earth = 6,378 \ km = 6,378,000 \ m\\\\G \ is \ the \ universal \ gravitation \ constant = 6.674 \times 10^{-11} Nm^2/kg^2\ \\\\Work \ done = \frac{(6.674 \times 10^{-11} ) \times (5.972\times 10^{24}) \times (16)}{6,378,000 } \\\\Work \ done = 9.998 \times 10^{8} \ J

Therefore, the work done by the gravitational field of the earth on the rock is 9.998 x 10⁸ J.

<u>To learn more about work done by gravitational field of the earth visit</u>: brainly.com/question/13934028

7 0
3 years ago
A piece of taffy slams into and sticks to another identical piece of taffy that is at rest. The momentum of the two pieces stuck
Yanka [14]

Answer:0.5

Explanation:

Given

Piece of taffy slams in to sticks to another identical  piece and stuck into it.

Let m be the mass of taffy and u be the initial velocity of taffy and v be the final velocity of system.

Conserving momentum

mu=2mv

v=\frac{u}{2}

Initial kinetic energy=\frac{mu^2}{2}

Final Kinetic Energy=\frac{2m(\frac{u}{2})^2}{2}=\frac{mu^2}{4}

change in kinetic energy \Delta K.E.=\frac{mu^2}{2}-\frac{mu^2}{4}=\frac{mu^2}{4}

change in kinetic energy will contribute in heat energy

thus fraction of kinetic energy converted in to heat =\frac{heat\ energy}{Initial\ kinetic\ Energy} =\frac{\frac{mu^2}{4}}{\frac{mu^2}{2}}=\frac{1}{2}=0.5

5 0
4 years ago
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