Gaseous neon has a density of 0.900 g/L at standard conditions. How many neon atoms are in 1.00 L of neon gas at standard condit

Question

3 years ago

11

ions?

1 answer:

Anvisha [2.4K] · Answer 1 · 2022-03-31T02:37:00+03:00

Answer: 1.348 ×10^23 atoms

Explanation:

Given that volume = 1.00L

At standard condition, the volume of a gas is 22.4L/mol (at S.T.P)

Volume = mole /volume at STP

1 = mole/22.4

Mole= 22.4mol.

Also

Mole = number of atoms /Avogradro constant

Where avogrado's constant = 6.02×10²³

22.4 = number of atoms/6.02×10²³

Number of atoms = 1.348×10^25atoms