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svet-max [94.6K]
3 years ago
11

PLEASE HELP WILL MARK BRAINLEST!!!!

Chemistry
1 answer:
puteri [66]3 years ago
6 0

Answer: c????????

Explanation:

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What is the minimum volume of 5.50 M HCl necessary to neutralize completely the hydroxide in 718.0 mL of 0.183 M NaOH
Deffense [45]

The volume of HCl required is 23.89 mL

Calculation of volume:

The reaction:

HCl + NaOH \rightarrow NaCl + H_2O

As HCl and NaOH react in 1 : 1 ratio.

Volume of NaOH= 718 mL

Concentration= 0.183M

Volume of HCl= ?

Concentration= 5.50M

Using the dilution formula:

M_1\times V_1(NaOH)= M_2\times V_2(HCl)

0.183\times 718= 5.50 \times V_2\\V_2=\frac{131.394}{5.50} \\V_2 = 23.89 \,mL

Therefore,

Volume of HCl required will be 23.89 mL.

Learn more about neutralization reaction here,

brainly.com/question/1822651

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2 years ago
What is the percent composition of Fluorine in CF5?
posledela
The answer is 100%
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3 years ago
Problem:
adelina 88 [10]

Answer:

it is Calcium (Ca)

4th period, 2nd group, 2 valence electrons

7 0
4 years ago
A sealed flask contains Ne, Ar, and Kr gas. If the total pressure in the flask is 3.782 atm, the partial pressure of Ne is 0.435
spin [16.1K]

Answer:

P_{Ar}=1.734atm = partial pressure of Ar

Explanation:

Acccoding to dalton's law of partial pressure total pressure of system is equal to alzebraic sum of all partial pressure.

P_{total} =P_{Ne}+P_{Ar} +P_{Kr}

P_{total}=3.782atm

P_{Ne}=0.435 atm

P_{Kr}=1.613atm

P_{Ar}=P_{total}-P_{Ne}-P_{Kr}

P_{Ar}=3.782-0.435-1.613

P_{Ar}=1.734atm =partial pressure of Ar

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