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3 years ago

5

The trait for flower color in a plant has red and white alleles. The red color is the dominant trait. What is the phenotypic rat

io for a cross between plants with red (Rr) flowers and white (rr) flowers?
4 red : 0 white
3 red : 1 white
2 red : 2 white
0 red : 4 white

1 answer:

Fudgin [204]3 years ago

6 0

Answer :

2 red : 2 white

Explanation:

;)long story short

hetro with hetro gives 3:1
hetro with recessive gives 1:1

Hetro :- ( Rr) one capital letter and one small
Recessive :- (rr) two small leters

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<u>Answer:</u> The $\Deltas H^o_{formation}$ for the reaction is -1406.8 kJ.

<u>Explanation:</u>

Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.

According to this law, the chemical equation is treated as ordinary algebraic expressions and can be added or subtracted to yield the required equation. This means that the enthalpy change of the overall reaction is equal to the sum of the enthalpy changes of the intermediate reactions.

The chemical reaction for the formation reaction of $AlCl_3$ is:

$2Al(s)+3Cl_2(g)\rightarrow 2AlCl_3 (s)$ $\Delta H^o_{formation}=?$

The intermediate balanced chemical reaction are:

(1) $HCl(g)\rightarrow HCl(aq.)$ $\Delta H_1=-74.8kJ$ ( × 6)

(2) $H_2(g)+Cl_2(g)\rightarrow 2HCl(g)$ $\Delta H_2=-185kJ$ ( × 3)

(3) $AlCl_3(aq.)\rightarrow AlCl_3(s)$ $\Delta H_3=+323kJ$ ( × 2)

(4) $2Al(s)+6HCl(aq.)\rightarrow 2AlCl_3(aq.)+3H_2(g)$ $\Delta H_4=-1049kJ$

The expression for enthalpy of formation of $AlCl_3$ is,

$\Delta H^o_{formation}=[6\times \Delta H_1]+[3\times \Delta H_2]+[2\times \Delta H_3]+[1\times \Delta H_4]$

Putting values in above equation, we get:

$\Delta H^o_{formation}=[(-74.8\times 6)+(-185\times 3)+(323\times 2)+(-1049\times 1)]=-1406.8kJ$

Hence, the $\Deltas H^o_{formation}$ for the reaction is -1406.8 kJ.

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<u>Answer:</u> The concentration of the solution is 0.25 M

<u>Explanation:</u>

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To calculate the molarity of the diluted solution, we use the equation:

$M_1V_1=M_2V_2$

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$M_1\text{ and }V_1$ are the molarity and volume of the concentrated NaCl solution

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$M_1=2.5M\\V_1=10mL\\M_2=?M\\V_2=100mL$

Putting values in above equation, we get:

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Hence, the concentration of the solution is 0.25 M

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