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iragen [17]
4 years ago
12

Which type of change releases a large amount of energy per gram of material as a result of the conversion of matter into energy?

Physics
2 answers:
kramer4 years ago
6 0
B.) "Nuclear Change" <span> releases a large amount of energy per gram of material as a result of the conversion of matter into energy

Hope this helps!</span>
VladimirAG [237]4 years ago
6 0
Your answer is B. nuclear
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I put +40 points!!!
Aleonysh [2.5K]

Answer:We can solve this using the Law of Conservation of Momentum. If both marbles are in our system, the initial momentum should equal the final momentum.

The initial momentum can be solved for as so:

*  +  =

(0.06)(0.7) + (0.03)(0) = 0.042 [kg * m/s]

So if the system has an initial momentum of 0.042, it should have the same final momentum.

(0.06)(-0.2) + (0.03)() = 0.042

(0.03)() = 0.54

() = 18 [m/s]

Explanation:

5 0
3 years ago
Read 2 more answers
Falculate the speed of a wave with frequency of 10KHz and wave length of 2m​
aleksklad [387]

Answer:20000m/s

Explanation:

Frequency=10khz

Frequency=10x1000

Frequency=10000hz

Wavelength=2m

Speed= frequency x wavelength

Speed=10000 x 2

Speed=20000

speed=20000m/s

8 0
4 years ago
What is true when an object is moved farther from a plane mirror?
musickatia [10]

Answer:

For a plane mirror, the image distance equals the object distance, so the image distance will increase as the object distance increases

The height of the image stays the same and the image distance increases.)

Explanation:

For plane mirrors, the object distance (is equal to the image distance. That is the image is the same distance behind the mirror as the object is in front of the mirror. If you stand a distance of 2 meters from a plane mirror, you must look at a location 2 meters behind the mirror in order to view your image

8 0
3 years ago
Why are denser materials found closer to earths center
ICE Princess25 [194]
Denser materials tend to be closer to earths center due to their mass gravity is shown by the equation mg
Which stands for mass x gravity.
5 0
3 years ago
As a science fair project, you want to launch an 950 g model rocket straight up and hit a horizontally moving target as it passe
Aleksandr-060686 [28]

Answer:

As a science fair project, you want to launch an 950g model rocket straight up and hit a horizontally moving target as it passes 33.0m above the launch point. The rocket engine provides a constant thrust of 20.0N . The target is approaching at a speed of 18.0m/s . At what horizontal distance between the target and the rocket should you launch?

= 43.56m

Explanation:

acceleration =

(20 - (0.95 * 9.8) )/ (0.95)

= 10.68 / 0.95

= 11.24 m/s²

we use

s = ut + (1/2) at²

Given that

s= 40

u =0  

s = 0 * t + (1/2) (11.24)t²

t = √(66/1.24)

t = √5.87

t = 2.42sec

hence

Horizontal distance = 18 * 2.42

= 43.56m

5 0
3 years ago
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