Explain why the<br> ball looks red<br> under normal<br> light.

Which three metal do you think might be present in alnico explain ? ans which one are magnetic

erma4kov [3.2K]

Answer:

Aluminium, Nickel, Cobalt and Iron plus varying levels of Copper, Titanium and Niobium.

MAGNETIC: Alni, Alcomax, Hycomax, Columax, and Ticonal.

8 0

3 years ago

Which of the following circuits can be used to measure the resistance of the heating element, shown as a resistor in the diagram

Wewaii [24]

In order to measure the resistance in the circuit, we need to know the voltage V and the current I in the circuit, this way we can calculate the resistance using the formula:

$R=\frac{V}{I}$

In order to calculate the current, we can use an amperemeter that must be in series with the circuit, this way it will not affect the circuit.

And in order to calculate the voltage, we can use a voltmeter that must be in parallel with the resistance, this way it will not affect the circuit.

The correct option that shows an amperemeter in series and a voltmeter in parallel is the fourth option.

8 0

1 year ago

All electromagnetic waves

ANEK [815]

Electromagnetic Waves:

Radio waves, television waves, and microwaves.

3 0

3 years ago

A car is traveling at 50 mi/h when the brakes are fully applied, producing a constant deceleration of 38 ft/s2. what is the dist

e-lub [12.9K]

Convert 38 ft/s^2 to mi/h^2. Then we se the conversion factor > 1 mile = 5280 feet and 1 hour = 3600 seconds.

So now we show it > $38 \frac{ft}{s^2} x \frac{1mi}{5280ft} x \frac{(3600s)^2}{(1h)^2} = 93272.27 \frac{mi}{h^2}$

Then we have to use the formula of constant acceleration to determine the distance traveled by the car before it ended up stopping.

Which the formula for constant acceleration would be > $v_2^2=v_1^2 + 2as$

The initial velocity is 50mi/h $(v_1=50)$

When it stops the final velocity is $(v_2=0)$

Since the given is deceleration it means the number we had gotten earlier would be a negative so a = -93272.27

Then we substitute the values in....

$0^2 = 50^2 + 2(-93272.27)s

0 = 2500 - 186544.54s

Isolate S next.

185644.54s= 2500

s = 2500/(185644.54)

s=0.0134
$

So we can say the car stopped at 0.0134 miles before it came to a stop but to express the distance traveled in feet we need to use the conversion factor of 1 mile = 5280 feet in otherwards > $0.0134 mi * \frac{5280ft}{1mi} = 70.8 ft$
So this means that the car traveled in feet 70.8 ft before it came to a stop.