Which element reacts spontaneously with 1.0M HCl (aq) at room temperature?
2 answers:
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An isotope of ₂₀⁴⁰X ⇒₂₀⁴⁴X
<h3>Further explanation </h3>The elements in nature have several types of isotopes
Isotopes are atoms that have the same number of protons and a different number of neutrons.
So Isotopes are elements that have the same Atomic Number (Proton)
In the following element notation,
X = symbol of elemental atom
A = mass number
= number of protons + number of neutrons
Z = atomic number
= number of protons = number of electrons, on neutral elements
For symbol of isotope X :
₂₀X⁴⁰ : atomic number = 20, mass number = 40
A. ₄₀²⁰X : atomic number = 40, mass number = 20, neutrons=20
B. ₂₀⁴⁰X²⁺ : atomic number = 20, mass number = 40, neutrons=20
C. ₂₁⁴⁰X : atomic number = 21, mass number = 40, neutrons=19
D. ₂₀⁴⁴X : atomic number = 20, mass number = 44, neutrons=22
Answer:
Kc = 1.54e - 31 / 2.61e - 24
Explanation:
1 ) ; Kc = 1.54e - 31
2) ; Kc = 2.16e - 24
upon reversing ( 2 ) equation
Kc = 1/2.16e - 24
now adding 1 and reversed equation (2)
we get ,
Kc = 1.54e-31 × 1/2.61e - 24
equilibrium constant of equation (3) is -
Kc = 1.54e - 31 / 2.61e - 24