They would most likely speed up.
A. Theresa is going to be my girl this year, he promised himself as he left the gym full of students in his new fall clothes.
Pressure of the gas inside the container is 662.59 torr.
<h3>What is ideal gas law?</h3>
The ideal gas law (PV = nRT) connects the macroscopic characteristics of ideal gases. An ideal gas is one in which the particles are both non-repellent and non-attractive to one another (have no volume).
The general law of ideal gas can be applied here: PV is equal to nRT, where P is the gas pressure in atm.
V is the number of moles of the gas in a mole, and n is the volume of the gas in L. R is the universal gas constant. T is the temperature(Kelvin) of the gas.
If P and T are different values and n and V are constants, then
(P₁T₂) = (P₂T₁).
P₁ = 735 torr, T₁ = 29°C + 273 = 302 K,
P₂ = ??? torr, T₂ = 62°C + 273 = 335 K.
∴ P₂ = (P₁T₂)/(P₁) = (735 torr)(302 K)/(335 K) = 662.59 torr.
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Answer:
20.79 kilojoules
Explanation:
Using Q = m×c×∆T
Where;
Q = Quantity of heat (J)
c = specific heat capacity of solid DMSO (1.80 J/g°C)
m = mass of DMSO
∆T = change in temperature
According to the provided information, m= 50g, initial temperature = 19.0°C, final temperature= 250.0°C
Q = m×c×∆T
Q = 50 × 1.80 × (250°C - 19°C)
Q = 90 × 231
Q = 20790 Joules
To convert Joules to kilojoules, we divide by 1000 i.e.
20790/1000
= 20.79 kilojoules
Hence, 20.79 kilojoules of energy is required to convert 50.0 grams of solid DMSO to gas.