Answer: The heat required to melt 25.0 g of ice at
is 8350 Joules
Explanation:
Heat of Fusion tells us how much energy is needed to convert 1g of a solid to a liquid at the same temperature.
Q = Heat absorbed = ?
m = mass of ice = 25.0 g
L = Latent heat of fusion of ice = 334 J/g
Putting in the values, we get:
Thus heat required to melt 25.0 g of ice at
is 8350 Joules
C is the answer i believe
It provides atomic mass, mass excess, nuclear binding energy, nucleon separation energies, Q-values, and nucleon residual interaction parameters for atomic nuclei of the isotope Na-24 (Sodium, atomic number Z = 11, mass number A = 24).