Answer:43.34 m
Explanation:
Given
acceleration(a)
Initial Velocity(u)=0 m/s
After 6 s fuel runs out
Velocity after 6 s
v=u+at
After this object will start moving under gravity
height reached in first 6 s
s=36 m
After fuel run out distance traveled in upward direction is
here v=0
u=12 m/s
Answer:
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288.51 N is the magnitude of the force that the beam exerts on the hi.nge.
Given
Mass 0f beam = 40 Kg
The horizontal component of the force exerted by the hi_nge on the beam is 86.62 N
Angle between the beam and cable is = 90°
Angle between beam and the horizontal component = 31°
As the system of the beam, hi_nge and cable are in equilibrium.
The magnitude of the force that the beam exerts on the hi_nge can be calculated by -
F =The horizontal component of force + the vertical component of force
F = 86.62 N + 40 × 9.8 × sin 31°
F =86.62 N + 201.89 N
F = 288.51 N
Hence, the magnitude of the force that the beam exerts on the hi_nge is 288.51 N.
Learn more about components of forces here brainly.com/question/26446720
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In my opinion, calling exercise "work" wouldn't be a good way of describing it, I don't think people would exercise if its called work
Answer:
If two forces act on an object in the same direction, the net force is the sum of the two forces. In this case, the net force is always greater than either of the individual forces.