Answer:
B) 2g
Explanation:
<u>Given the following data;</u>
Velocity, v = 14m/s
Radius, r = 10m
To find the centripetal acceleration;
Substituting into the equation, we have;
Acceleration, a = 19.6m/s²
In terms of acceleration due to gravity, g = 9.8m/s²
We would divide by g;
Acceleration, a = 19.6/9.8 = 2
Hence, centripetal acceleration = 2g
Therefore, the rider's centripetal acceleration in terms of g, the acceleration due to gravity is 2g.
Answer:
Average velocity is 0.296 m/s.
Average speed is 4.0 m/s.
Explanation:
Given:
Distance of the circular track is, 
Number of laps ran is, 
Time taken for the run is, 
Now, total distance covered in 5.4 laps = 
Also, since the path is a circle, the final position of the athlete after 5.4 laps will be 0.4 of 400 m ahead of the starting point.
Distance covered in 0.4 laps is, 
Therefore, the displacement of the athlete will be 160 m as the athlete is 160 m ahead of the starting point and displacement depends on the initial and final points only.
Now, average velocity is given as:

Average speed is the ratio of total distance covered to total time taken.
So, average speed = 
Answer:
a) 3.7 m/s^2
b) 231.8 N
Explanation:
Let m1 be mass of the first object (m1 = 38.0 kg) and let m2 be the mass of the second object (m2 = 17.0 kg ). Let a be the acceleration of the two objects. Let F1 be the force of gravity exerted on m1 and F2 be the force of gravity exerted on m2. Let M = m1 +m2
a)
F1 = m1g and F2 = m2g
So Fnet = F1 + F2
Since the pulleys will move in different directions when accelerating...
Fnet = F1 - F2
M×a = m1g - mg2
M×a = g×(m1 -m2)
a = g×(m1 - m2)/M
a = 9.8×(38 - 17)/(38 + 17)
a = 3.7 m/s^2
b)
Looking at the part for m2
Fnet = T - m2g
-m2×a = T - m2g
T = m2(g - a)
T = 231.8 N
"B" When an object moves away from us, the light is shifted to the red end of the spectrum, as its wavelengths get longer.
Answer:
It tells us that the element has 6 electrons in it's shells
Explanation: