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jasenka [17]
3 years ago
8

The citric acid cycle (cac) is activated in the presence of oxygen, but what is the link between the cac and oxygen? pick the on

e best choice:
a.oxygen is an allosteric activator for citrate synthase.
b. the presence of o2 in the mitochondrial matrix releases co2 into the cytosol.
c.the one substrate-level phosphorylation in the cac can occur in the absence of oxygen.
d. the major product of the cac is nadh, the principle electron donor to the o2 , the last electron acceptor in the electron-transport system.
e. the major product of the cac is fadh2 , the principle electron donor to the o2 , the last electron acceptor in the electron-transport system.
Chemistry
1 answer:
Pani-rosa [81]3 years ago
4 0
The answer in this question which is asking about the link between the CAC and oxygen is that  the major product of the cac is nadh, the principle electron donor to the o2 , the last electron acceptor in the electron-transport system. The answer in this question is D.
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For the process 2SO2(g) + O2(g) --> 2SO3(g),
CaHeK987 [17]

Answer:

–187.9 J/K

Explanation:

The equation that relates the three quantities is:

\Delta G = \Delta H - T \Delta S

where

\Delta G is the Gibbs free energy

\Delta H is the change in enthalpy of the reaction

T is the absolute temperature

\Delta S is the change in entropy

In this reaction we have:

ΔS = –187.9 J/K

ΔH = –198.4 kJ = -198,400 J

T = 297.0 K

So the Gibbs free energy is

\Delta G=-198,400-(297.0)(-187.9)=254.2 kJ

However, here we are asked to say what is the entropy of the reaction, which is therefore

ΔS = –187.9 J/K

8 0
3 years ago
An oxide of phosphorus contains 56.4% phosphorus and 43.6% oxygen. It's relative molecular mass is 220. Find both the empirical
sladkih [1.3K]
Moles of P = 56,4g/30,974g/mole = 1,82 moles P
moles of O = 43,6/15,999 = 2,73 moles of O

converting to the simplest ratio:
For P : 1,82/1,82 = 1
For O : 2,73/1,82 = 1,5

1 P and 2 oxygens.
PO2 -> the empirical formula

hope this help
7 0
3 years ago
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BartSMP [9]

Answer:D.

Explanation:

4 0
3 years ago
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valentina_108 [34]

Answer:

C ) 2, 1, 2

Explanation:

The given reaction is synthesis reaction in which lithium and bromine react to form lithium bromide.

Chemical equation:

Li + Br₂    →    LiBr

Balanced chemical equation:

2Li + Br₂    →    2LiBr

Step 1:

Li + Br₂    →    LiBr

left hand side                         Right hand side

Li = 1                                        Li = 1

Br = 2                                        Br = 1

Step 2:

Li + Br₂    →    2LiBr

left hand side                         Right hand side

Li = 1                                        Li = 2

Br = 2                                        Br = 2

Step 3:

2Li + Br₂    →    2LiBr

left hand side                         Right hand side

Li = 2                                       Li = 2

Br = 2                                        Br = 2

3 0
3 years ago
Elements in the same period have _____.
faust18 [17]

Ans: Elements in the same period have the same number of electron shells.

4 0
2 years ago
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