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kow [346]
3 years ago
13

Choose true or false for each statement regarding a parallel plate capacitor.. The voltage of a disconnected charged capacitor i

ncreases when the plate area is decreased. The electric field is dependent on the charge density on the plates. The voltage of a connected charged capacitor remains the same when the plate area is decreased.
Physics
1 answer:
OlgaM077 [116]3 years ago
3 0

Answer:

Explanation:

The voltage of a disconnected charged capacitor increases when the plate area is decreased.

When plate area decreases , capacitance C decreases , but charge Q remains constant .

Q = C V where C is capacitance and V is voltage .

when C decreases , V increases for keeping Q constant .

So the statement is true.

The electric field is dependent on the charge density on the plates.

This statement is true .

The voltage of a connected charged capacitor remains the same when the plate area is decreased .

For a connected capacitor , V or voltage is constant which is equal to voltage of charging battery .

So the statement is true .

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Calculate the capacitance of a system that stores 9.4 x 10-10 C of charge at
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The capacitance of the system is 1.9\cdot 10^{-11}F

Explanation:

The capacitance of a capacitor is given by the following equation:

C=\frac{Q}{V}

where

C is the capacitance

Q is the charge stored in the capacitor

V is the potential difference across the capacitor

In this problem, we have:

Q=9.4\cdot 10^{-10}C is the charge stored

V=50.0 V is the potential difference across it

Substituting into the equation, we find the capacitance:

C=\frac{9.4\cdot 10^{-10}}{50.0}=1.9\cdot 10^{-11}F

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2 years ago
How does the loneliest whale relate to physics/waves.
Lelechka [254]
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3 years ago
In being served, a tennis ball is accelerated from rest to a speed of 31.6 m/s. The average power generated during the serve is
joja [24]

Answer:

The force acting on the ball is 92.4 N.

Explanation:

Given that,

Initial speed of the ball, u = 0

Final speed of the ball, v = 31.6 m/s

The average power generated during the serve is 2920 W. Power generated by an object is given by :

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W is the work done, W = Fd

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Since, v=\dfrac{d}{t}

So,

P=F\times v

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F=\dfrac{P}{v}\\\\F=\dfrac{2920\ W}{31.6\ m/s}\\\\F = 92.4\ N

So, the force acting on the ball is 92.4 N. Hence, this is the required solution.

7 0
3 years ago
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